QUESTION 5: Consider the differential amplifier in Figure P11.17 with parameters V = 5 V, V = -5 V, and Io = 0.8 mA.Neglect base currents and assume V₁ = ∞ for all transistors.The emitter currents can be written as I£1 = IS1 EXP(VBE1/VT) and I£2 = 152 EXP(VBE2/VT).If v₁ = v₂ = 0, Is1 = 2.3 x 10-¹5 A and Is2 = 2.2 x 10-¹5 A, determine (v01 - v0₂) for Rc₁ = 7.2 k and Rc2 = 7.9 kq.IE1 (mA)Format : 0.3093IE2 (mA)Format : 0.5634(V01 - V02) (V)Format: 0.5862V+R₁2₁Rc1VOIRc2OV022₂VFigure P11.17V₂24

Differential amplifier It is an electric circuit that amplifies the difference between two input…

QUESTION 5: Consider the differential amplifier in Figure P11.17 with parameters V = 5 V, V = -5 V, and Io = 0.8 mA. Neglect base currents and assume V₁ = ∞ for all transistors. The emitter currents can be written as IE1 = IS1 EXP(VBE1/VT) and IE2 = IS2 EXP(VBE2/VT). If v₁ = v₂ = 0, Is₁ = 2.3 x 10-15 A and Is2 = 2.2 x 10-¹5 A, determine (vo₁ - v0₂) for Rc₁ = 7.2 kN and Rc2 = 7.9 kq. IE1 (mA) Format: 0.3093 IE2 (mA) Format: 0.5634 (V01-V0₂) (V) Format: 0.5862 V+ R₁ RC Rc2 VOI V02 ww 2₂ Tos Figure P11.17 V2 24

QUESTION 5: Consider the differential amplifier in Figure P11.17 with parameters V = 5 V, V = -5 V, and Io = 0.8 mA. Neglect base currents and assume V₁ = ∞ for all transistors. The emitter currents can be written as IE1 = IS1 EXP(VBE1/VT) and IE2 = IS2 EXP(VBE2/VT). If v₁ = v₂ = 0, Is₁ = 2.3 x 10-15 A and Is2 = 2.2 x 10-¹5 A, determine (vo₁ - v0₂) for Rc₁ = 7.2 kN and Rc2 = 7.9 kq. IE1 (mA) Format: 0.3093 IE2 (mA) Format: 0.5634 (V01-V0₂) (V) Format: 0.5862 V+ R₁ RC Rc2 VOI V02 ww 2₂ Tos Figure P11.17 V2 24

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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