Question 4Suppose we are testing the null hypothesis Ho: p=0.3, and want to use a significance level ofa = 0.05. What sample size should we use if we want a power [probability to correctly reject Ho inthe proper direction] of 75% when the true proportion is p = 0.35? Please round up and reportyour answer to the next highest whole number.Question 5Suppose we are testing the null hypothesis Ho: p=0.4, and will gather data from N = 200respondents. If we are using a 90% confidence interval, what is the power of our test to detect ifthe true proportion was p = 0.3? Please round your answer to 2 decimal places; do NOT convert toa percentage.Question 6Suppose we are testing the null hypothesis Ho: p= 0.85, and will gather data from N= 318respondents. If we are using a 95% confidence interval, what is the power of our test to detect ifthe true proportion was p = 0.82? Please round your answer to 2 decimal places; do NOT convertto a percentage.

Question 4: Given Information: Null Hypothesis H0:p=0.3 Alternative Hypothesis Ha:p>0.3…

Answered: Question 4 Suppose we are testing the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The genders from 100 births at a certain hospital are provided, where 1 = boy and 0= girl. Use a 0.05 significance level to test the claim that the sequence, from left to right and then top bottom, is random. Click the icon to view the sequence of birth genders. Determine the null and alternative hypotheses. Ho: H₁: The data are in a random order. The data do not alternate above and below the mean a lot. The number of boys born at the hospital is the same as the number of girls. The data alternate above and below the mean a lot. There are more boys than girls born at the hospital. The number of boys born at the hospital differs from the number of girls. The data are in an order that is not random. There are more girls than boys born at the hospital. Birth Genders 0 1 0 1 1 0010 0 1 1 1 1 0 1 0 1 0 1 0 1 0 1 1 1 1 0 01 1 0 1 0 1 1 0 1 0 10 à 10000 1 0 0 1 0 1 0 1 1 3 1 0 0 0 1 0 1 0 1 0 1 1 0 0 1 1 1 1 1 1 0 1 0 0 17 100 10 0 0 1 1 0 00011 8 0 1 1 0 1 0 1 1 1 1 101 1 0 1 0 1 0 0 0 1 0…
You compute a two-sample z statistic and it comes out to equal 1.45. What is the p-value if you are doing a two-tailed test?
Next Question A data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n= 184, x = 6.51, s = 2.05. Use a 0.10 significance level to test the claim that the population mean of such ratings is less than 7.00. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho:H7.00 O B. Ho: H=7.00 H:H>7.00 OC. Ho:H=7.00 H:u#7.00 O D. Ho: H= 7.00 H:H<7.00 Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence to conclude that the mean of the population of ratings is 7.00. Click to select your answer(s). esc %23 24 5 6 3 T. Q W E tab J K G * 00 F.
In lecture, we analyzed the simulated results of rolling five normal dice a total of 1,000 times. We determined that the mean of the distribution of sample means was about 3.5, which is the mean of the population of rolls {1, 2, 3, 4, 5, 6}. We also determined that the mean of the sample proportions for odd rolls was about 0.5. This agreed with the population result, where 3/6 numbers in the population are odd. How would you expect these results to change if each of the five dice were weighted according to the table below? In particular, how would this affect the mean of the distribution of sample means? The mean of the distribution of sample proportions for odd rolls? Discuss from a qualitative perspective. You do not need to perform any calculations here. Roll Probability 1 0.1 2 0.1 3 0.1 4 0.4 0.1 6. 0.2
Which of the following is TRUE? A. As the number of observations increases, trit also increases B. Fcrit increases as the level of significance decreases. C. In ANOVA with 3 groups and a total sample size of 33, p will be less than 0.05 if the computed F value is 2.01. D. All are true
A suggestion is made that the proportion of people who have food allergies and/or sensitivities is 0.53. You believe that the proportion is actually less than 0.53. The hypotheses for this test are Null Hypothesis: p > 0.53, Alternative Hypothesis: p < 0.53. If you select a random sample of 27 people and 18 have a food allergy and/or sensitivity, what is your test statistic and p-value? 1) Test Statistic: 1.423, P-Value: 0.923 2) Test Statistic: -1.423, P-Value: 0.077 3) Test Statistic: -1.423, P-Value: 0.923 4) Test Statistic: 1.423, P-Value: 0.077 5) Test Statistic: 1.423, P-Value: 1.846
Suppose you want to perform a test of ?0:?=64�0:�=64 versus ?0:?≠64�0:�≠64 at the ?=0.05�=0.05 significance level. A random sample of size ?=25�=25 from the population of interest yields ?¯=62.8�¯=62.8 and ??=5.36��=5.36 . Assume that the conditions for carrying out the test are met. Calculate the standardized test statistic and the ?�-value
See below. I need help with the two items in the red boxes. NOTE: THOSE TWO ANSWERS ARE WRONG!!!
should we accept or reject the null hypothesis at a significance level of 0.05? Explain.
A news article that you read stated that 56% of voters prefer the Democratic candidate. You think that the actual percent is larger. 142 of the 236 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.10 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly larger 56% at αα = 0.10, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is larger 56% The data suggest the population proportion is not significantly larger 56% at αα = 0.10, so…
Given two independent random samples with the following results: n₁ = 651 n2 = 569 x₁ = 307 x2 = 234 Can it be concluded that there is a difference between the two population proportions? Use a significance level of a = 0.02 for the test. Copy Data Step 3 of 6: Compute the weighted estimate of p, p. Round your answer to three decimal places.
A news article that you read stated that 54% of voters prefer the Democratic candidate. You think that the actual percent is larger. 157 of the 249 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion Correct The null and alternative hypotheses would be: Ho: ? p μ Correct Select an answer ≠ > < = (please enter a decimal) H1: ? μ p Correct Select an answer > < = ≠ (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis.

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