Box answer Question 4 (Matrix exponential method)Question 4. LetA-(33)4(i) Find eA.(ii) Find the general solution of the system below using the matrix exponential method.37- (11) 7.(iii) Solve the initial value problem3-(33) 7. y(0)(0) - (2).43

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Answered: Question 4 (Matrix exponential method)…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter9: Systems Of Equations And Inequalities

Section9.7: The Inverse Of A Matrix

Problem 32E

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Epidemic Model In a population of 200,000 people, 40,000 are infected with a virus. After a person becomes infected and then recovers, the person is immune cannot become infected again. Of the people who are infected, 5 will die each year and the other will recover. Of the people who have never been infected, 25 will become infected each year. How many people will be infected in 4 years?
Explain the differences between Gaussian elimination and Gauss-Jordan elimination.
3. Solve the system by using the matrix exponential -2 3 *-*-*-] x' = x (2) -1 2 4
Needed to be Solved Q2 correctly and get the thumbs up please show neat and clean work. Please provide correct solution only and take your time
2b) Differential Equations: please correctly
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the equation of motion of a particle is given by subject to the initial conditions Xo = x1 x₁ = -ao xo - α₁ x₁ (x0, X1) = (1, 0) The constants are given as follows: a = 2 and a₁ = 1 (a) Find the solutions of the equations of motion using the RK(solver_ivp) method of solving system ODES. (b) What do the constants ao and a₁ represent physically? You can use dimensional analysis. (c) Describe the motion based on your results.
Please help me to solve the system of ODE's ((question 4)) in the below of page 4.I attached an explanation with the question 3 for your helpThank you.[ Math. modeling ]
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The solution of the system X'= O a. Ob. C. 1 -2t Xx=₁₂ (²1²¹)]0-²² + 0₂( ²₁) ²0²-²² X=C1 te-2t te O d. -3 -1 1 -1 x = c₂₁( -2t C₂ 1-C₂ ( ²2² ) = -²² + c =( ^1^²) 060-²2² + ₂(1 c3( ) e X=C1 x is -2t C le ²xX = ₁₂₁( ²7² ) 0 -² ² + 0₂( 2² ) 0² + X=C1 Oe. none of the above 2t 2t ¯₁²¹) 0−²² + c₂{[(^~^²) te-²² + ( ² )0−²ª] 2t -2t
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Question 4 (Matrix exponential method) Question 4. Let A-(33) 4 (i) Find eA. (ii) Find the general solution of the system below using the matrix exponential method. 3 7- (11) 7. (iii) Solve the initial value problem 3 -(33) 7. y(0) (0) - (2). 43