Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 O First-order, k = 0.210 hour CO First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1-hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M1 hour 1 Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 pts
Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 O First-order, k = 0.210 hour CO First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1-hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M1 hour 1 Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 pts
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 4E: A study of the rate of dimerization of C4H6 gave the data shown in the table: 2C4H6C8H12 (a)...
Related questions
Question
![Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
O First-order, k = 0.210 hour
CO First-order, k = 0.0912 hour 1
O Second-order, k = 0.590 M1-hour 1
O Zero-order, k = 0.0770 M/hour
O Zero-order, k = 0.4896 M/hour
O Second-order, k = 1.93 M1 hour 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8fcee6be-bdc8-4ecd-9059-539f49560d00%2F3d4389a6-dd33-4b60-8140-f74629cff701%2F5cce4j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
O First-order, k = 0.210 hour
CO First-order, k = 0.0912 hour 1
O Second-order, k = 0.590 M1-hour 1
O Zero-order, k = 0.0770 M/hour
O Zero-order, k = 0.4896 M/hour
O Second-order, k = 1.93 M1 hour 1
![Question 4
Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
First-order, k = 0.210 hour 1
First-order, k = 0.0912 hour 1
O Second-order, k =
0.590 M1 hour 1
O Zero-order, k = 0.0770 M/hour
O Zero-order, k = 0.4896 M/hour
O Second-order, k = 1.93 M-1-hour 1
10 pts](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8fcee6be-bdc8-4ecd-9059-539f49560d00%2F3d4389a6-dd33-4b60-8140-f74629cff701%2Fv0z18c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 4
Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
First-order, k = 0.210 hour 1
First-order, k = 0.0912 hour 1
O Second-order, k =
0.590 M1 hour 1
O Zero-order, k = 0.0770 M/hour
O Zero-order, k = 0.4896 M/hour
O Second-order, k = 1.93 M-1-hour 1
10 pts
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