Question 3 OF A learner was assigning oxidation numbers for different elements in the compounds OF and NaF. The learner assigned F an oxidation number of +1 in 2 and -1 in NaF. Is this correct? Why? A Yes this is correct. B No, fluorine is always assigned an oxidation number of -1. с No, fluorine is always assigned an oxidation number of +1. D No, fluorine is always assigned an oxidation number of -1 except when bonded to 2

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A learner was assigning oxidation numbers for different elements in the compounds OF2 and NaF. The learner assigned F an oxidation number of +1 in OF2 and –1 in NaF.

Is this correct? Why?

**Question 3**

A learner was assigning oxidation numbers for different elements in the compounds \( \text{OF}_2 \) and \( \text{NaF} \). The learner assigned \( \text{F} \) an oxidation number of \( +1 \) in \( \text{OF}_2 \) and \( -1 \) in \( \text{NaF} \).

Is this correct? Why?

Options:
- **A:** Yes, this is correct.
- **B:** No, fluorine is always assigned an oxidation number of \( -1 \).
- **C:** No, fluorine is always assigned an oxidation number of \( +1 \).
- **D:** No, fluorine is always assigned an oxidation number of \( -1 \) except when bonded to oxygen.

**Explanation:**
- **A:** This option asserts the learner's assignments are correct without providing a basis.
- **B:** This option proposes that fluorine always has an oxidation number of \( -1 \).
- **C:** This option proposes that fluorine always has an oxidation number of \( +1 \).
- **D:** This option proposes that fluorine usually has an oxidation number of \( -1 \) but may differ when bonded to oxygen.

To determine which answer is correct, we need to assess the rules for assigning oxidation numbers:
1. Fluorine is the most electronegative element and usually has an oxidation number of \( -1 \) in most compounds.
2. In \( \text{NaF} \), sodium (Na) has an oxidation number of \( +1 \), making fluorine (F) \( -1 \), which is typical.
3. In \( \text{OF}_2 \), oxygen is less electronegative than fluorine. Thus, fluorine would have an oxidation number of \( -1 \), and oxygen’s oxidation number adjusts accordingly.

From the options provided, the correct response is:

- **D:** No, fluorine is always assigned an oxidation number of \( -1 \) except when bonded to oxygen.

This explanation highlights the specific exception relevant to \( \text{OF}_2 \) and follows the rules for assigning oxidation numbers accurately.
Transcribed Image Text:**Question 3** A learner was assigning oxidation numbers for different elements in the compounds \( \text{OF}_2 \) and \( \text{NaF} \). The learner assigned \( \text{F} \) an oxidation number of \( +1 \) in \( \text{OF}_2 \) and \( -1 \) in \( \text{NaF} \). Is this correct? Why? Options: - **A:** Yes, this is correct. - **B:** No, fluorine is always assigned an oxidation number of \( -1 \). - **C:** No, fluorine is always assigned an oxidation number of \( +1 \). - **D:** No, fluorine is always assigned an oxidation number of \( -1 \) except when bonded to oxygen. **Explanation:** - **A:** This option asserts the learner's assignments are correct without providing a basis. - **B:** This option proposes that fluorine always has an oxidation number of \( -1 \). - **C:** This option proposes that fluorine always has an oxidation number of \( +1 \). - **D:** This option proposes that fluorine usually has an oxidation number of \( -1 \) but may differ when bonded to oxygen. To determine which answer is correct, we need to assess the rules for assigning oxidation numbers: 1. Fluorine is the most electronegative element and usually has an oxidation number of \( -1 \) in most compounds. 2. In \( \text{NaF} \), sodium (Na) has an oxidation number of \( +1 \), making fluorine (F) \( -1 \), which is typical. 3. In \( \text{OF}_2 \), oxygen is less electronegative than fluorine. Thus, fluorine would have an oxidation number of \( -1 \), and oxygen’s oxidation number adjusts accordingly. From the options provided, the correct response is: - **D:** No, fluorine is always assigned an oxidation number of \( -1 \) except when bonded to oxygen. This explanation highlights the specific exception relevant to \( \text{OF}_2 \) and follows the rules for assigning oxidation numbers accurately.
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