A standardized 0.83 M solution of KMnO4 is titrated against a 16 mL sample of an unknown analyte containing Fe2+. An analyst performed the redox titration and reaches the endpoint after adding 23.93 mL of the titrant. What is the concentration of the analyte? MnO4 + Fe²+ ⇒ Fe³+ + Mn2+ Answer in 2 decimal places, unit is not required.

A standardized 0.83 M solution of KMnO4 is titrated against a 16 mL sample of an unknown analyte containing Fe2+. An analyst performed the redox titration and reaches the endpoint after adding 23.93 mL of the titrant. What is the concentration of the analyte? MnO4 + Fe²+ ⇒ Fe³+ + Mn2+ Answer in 2 decimal places, unit is not required.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Malic acid (C4H6O5) is a dicarboxylic acid that naturally occurs in the production of bignay wine. Maria was tasked to find out the acid content in a 200.0 mL wine sample by titrating it with a standardized solution of KOH. He was able to establish the working concentration of the KOH solution by using 39.12 mL of it to titrate a primary standard of KHP that weighed 3.021 g. The grams and %w/w of Malic acid present in the 200.0 mL wine sample were then determined by titrating a 20.00 mL aliquot using 48.95 mL of the standardized KOH solution. C4H6O5 (aq) + 2KOH (aq) ↔ K2C4H4O5 (aq) + 2H2O (l) Assume the density of the wine sample is 1.000 g/mL MM of KHP = 204.22 g/mol MM of C4H6O5 = 134.0874 g/mol What is the molar concentration of the prepared KOH solution?…
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