QUESTION 25 When 2.5 moles of calcium carbonate is added to 4.8 moles of hydrochloric acid, calcium chloride, carbon dioxide, and water are produced: CaCO3(s) + 2HCl(aq) →CaCl₂(aq) +H₂O(l) + CO₂(g) Which equation below represents the calculation for the number of grams of calcium chloride that are produced if the reaction proceeds with a 65% yield? A. 2.5 moles CaCl₂ * 110.98 grams/mol * 0.65 B. 2.4 moles CaCl₂ * 110.98 grams/mol * 0.65 C. 2.5 moles CaCl₂ * 110.98 grams/mol / 0.65 D. 2.4 moles CaCl₂ * 110.98 grams/mol / 0.65 ΟΟΟΟ A B C D
QUESTION 25 When 2.5 moles of calcium carbonate is added to 4.8 moles of hydrochloric acid, calcium chloride, carbon dioxide, and water are produced: CaCO3(s) + 2HCl(aq) →CaCl₂(aq) +H₂O(l) + CO₂(g) Which equation below represents the calculation for the number of grams of calcium chloride that are produced if the reaction proceeds with a 65% yield? A. 2.5 moles CaCl₂ * 110.98 grams/mol * 0.65 B. 2.4 moles CaCl₂ * 110.98 grams/mol * 0.65 C. 2.5 moles CaCl₂ * 110.98 grams/mol / 0.65 D. 2.4 moles CaCl₂ * 110.98 grams/mol / 0.65 ΟΟΟΟ A B C D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter10: Liquids And Solids
Section: Chapter Questions
Problem 1RQ: What are intermolecular forces? How do they differ from intramolecular forces? What are...
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![QUESTION 25
When 2.5 moles of calcium carbonate is added to 4.8 moles of
hydrochloric acid, calcium chloride, carbon dioxide, and water are
produced: CaCO3(s) + 2HCl(aq) → CaCl₂(aq) +H₂O(l) + CO₂(g)
Which equation below represents the calculation for the number of
grams of calcium chloride that are produced if the reaction proceeds
with a 65% yield?
A. 2.5 moles CaCl₂ * 110.98 grams/mol * 0.65
B. 2.4 moles CaCl₂ * 110.98 grams/mol * 0.65
C. 2.5 moles CaCl₂ * 110.98 grams/mol / 0.65
D. 2.4 moles CaCl₂ * 110.98 grams/mol / 0.65
OA
B
C
OD](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38650a9c-63f5-423f-8b89-b03c0dad949f%2F5da72ebe-4b21-44cd-b633-5895a130a4f1%2F4uy3qrp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 25
When 2.5 moles of calcium carbonate is added to 4.8 moles of
hydrochloric acid, calcium chloride, carbon dioxide, and water are
produced: CaCO3(s) + 2HCl(aq) → CaCl₂(aq) +H₂O(l) + CO₂(g)
Which equation below represents the calculation for the number of
grams of calcium chloride that are produced if the reaction proceeds
with a 65% yield?
A. 2.5 moles CaCl₂ * 110.98 grams/mol * 0.65
B. 2.4 moles CaCl₂ * 110.98 grams/mol * 0.65
C. 2.5 moles CaCl₂ * 110.98 grams/mol / 0.65
D. 2.4 moles CaCl₂ * 110.98 grams/mol / 0.65
OA
B
C
OD
![Octane (C8H₁8) is a straight chain of carbon atoms with no dipole
moment and a boiling point of 125°C. Water has a dipole moment,
can hydrogen bond and has a boiling point of 100°C. The difference
between these two boiling points can best be rationalized by:
A. Intermolecular forces between molecules with dipole moments
are greater than between molecules with no dipole moment
B. Hydrogen bonding is a strong intermolecular force
C. London dispersion forces are weak but there are many LDFs in
octane so the net IMF in C8H₁8 is greater than the net IMF in H₂O
D. London dispersion forces are strong and so the boiling point of
octane is greater than the boiling point of water
O A
OB
O C
OD](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38650a9c-63f5-423f-8b89-b03c0dad949f%2F5da72ebe-4b21-44cd-b633-5895a130a4f1%2F84ynjbg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Octane (C8H₁8) is a straight chain of carbon atoms with no dipole
moment and a boiling point of 125°C. Water has a dipole moment,
can hydrogen bond and has a boiling point of 100°C. The difference
between these two boiling points can best be rationalized by:
A. Intermolecular forces between molecules with dipole moments
are greater than between molecules with no dipole moment
B. Hydrogen bonding is a strong intermolecular force
C. London dispersion forces are weak but there are many LDFs in
octane so the net IMF in C8H₁8 is greater than the net IMF in H₂O
D. London dispersion forces are strong and so the boiling point of
octane is greater than the boiling point of water
O A
OB
O C
OD
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