If 10.0 moles of O: are reacted with excess NO in the reaction below, and only 5.5 mol of NO2 were collected, then what is the percent yield for the reaction? 2 NO (g) + O2 (g)→2 NO2 (g)

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Chapter1: Chemical Foundations
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**Question:**

If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 5.5 mol of NO₂ were collected, then what is the percent yield for the reaction?

2 NO (g) + O₂ (g) → 2 NO₂ (g)

**Explanation:**

This question examines the concept of percent yield in chemical reactions. Percent yield is calculated using the formula:

\[
\text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100\%
\]

- **Theoretical Yield Calculation:** Using stoichiometry, 10.0 moles of O₂ could theoretically produce 20.0 moles of NO₂, considering the reaction 2 NO + O₂ → 2 NO₂.
- **Actual Yield:** The actual amount of NO₂ collected is 5.5 moles.
  
**Solution:**

1. Calculate the theoretical yield of NO₂ based on O₂ as the limiting reactant.
2. Use the percent yield formula to find the answer.

**Calculator Interface:**

The image has a calculator interface on the right side with numbers (1-9, 0), arithmetic symbols, and a 'percent' button, presumably to assist in carrying out the calculation electronically.
Transcribed Image Text:**Question:** If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 5.5 mol of NO₂ were collected, then what is the percent yield for the reaction? 2 NO (g) + O₂ (g) → 2 NO₂ (g) **Explanation:** This question examines the concept of percent yield in chemical reactions. Percent yield is calculated using the formula: \[ \text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100\% \] - **Theoretical Yield Calculation:** Using stoichiometry, 10.0 moles of O₂ could theoretically produce 20.0 moles of NO₂, considering the reaction 2 NO + O₂ → 2 NO₂. - **Actual Yield:** The actual amount of NO₂ collected is 5.5 moles. **Solution:** 1. Calculate the theoretical yield of NO₂ based on O₂ as the limiting reactant. 2. Use the percent yield formula to find the answer. **Calculator Interface:** The image has a calculator interface on the right side with numbers (1-9, 0), arithmetic symbols, and a 'percent' button, presumably to assist in carrying out the calculation electronically.
Expert Solution
Step 1

The given reaction is as follows:

2NO(g) + O2(g)------->2NO2(g)

The moles of O2 reacting, = 10 moles.

The moles of NO2 formed = 5.5 moles.

 

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