If 10.0 moles of O: are reacted with excess NO in the reaction below, and only 5.5 mol of NO2 were collected, then what is the percent yield for the reaction? 2 NO (g) + O2 (g)→2 NO2 (g)
If 10.0 moles of O: are reacted with excess NO in the reaction below, and only 5.5 mol of NO2 were collected, then what is the percent yield for the reaction? 2 NO (g) + O2 (g)→2 NO2 (g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![**Question:**
If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 5.5 mol of NO₂ were collected, then what is the percent yield for the reaction?
2 NO (g) + O₂ (g) → 2 NO₂ (g)
**Explanation:**
This question examines the concept of percent yield in chemical reactions. Percent yield is calculated using the formula:
\[
\text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100\%
\]
- **Theoretical Yield Calculation:** Using stoichiometry, 10.0 moles of O₂ could theoretically produce 20.0 moles of NO₂, considering the reaction 2 NO + O₂ → 2 NO₂.
- **Actual Yield:** The actual amount of NO₂ collected is 5.5 moles.
**Solution:**
1. Calculate the theoretical yield of NO₂ based on O₂ as the limiting reactant.
2. Use the percent yield formula to find the answer.
**Calculator Interface:**
The image has a calculator interface on the right side with numbers (1-9, 0), arithmetic symbols, and a 'percent' button, presumably to assist in carrying out the calculation electronically.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1ddd161-3ca4-4c60-945b-e9699d5519ef%2Ffe538af5-9eed-42fe-a425-5a8f8e027851%2Fdunh9j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 5.5 mol of NO₂ were collected, then what is the percent yield for the reaction?
2 NO (g) + O₂ (g) → 2 NO₂ (g)
**Explanation:**
This question examines the concept of percent yield in chemical reactions. Percent yield is calculated using the formula:
\[
\text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100\%
\]
- **Theoretical Yield Calculation:** Using stoichiometry, 10.0 moles of O₂ could theoretically produce 20.0 moles of NO₂, considering the reaction 2 NO + O₂ → 2 NO₂.
- **Actual Yield:** The actual amount of NO₂ collected is 5.5 moles.
**Solution:**
1. Calculate the theoretical yield of NO₂ based on O₂ as the limiting reactant.
2. Use the percent yield formula to find the answer.
**Calculator Interface:**
The image has a calculator interface on the right side with numbers (1-9, 0), arithmetic symbols, and a 'percent' button, presumably to assist in carrying out the calculation electronically.
Expert Solution
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Step 1
The given reaction is as follows:
2NO(g) + O2(g)------->2NO2(g)
The moles of O2 reacting, = 10 moles.
The moles of NO2 formed = 5.5 moles.
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