Question 22 Let X equal the number of bits in error in the next four bits transmitted. The possible values for X are {0, 1, 2, 3, 4} Suppose that the probabilities are points Save Alls P(x =0)-0.45 P(x=1)-D0.19 P(x 2)-0.15 P(x=3)3D0.10 P(x-4)3D0.10 Find E(X) Oa 1.19 Ob 0.35 Oc 22 Od o

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Question 22
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Let X equal the number of bits in error in the next four bits transmitted. The possible values for X are {0, 1, 2,
3, 4} Suppose that the probabilities are
Р(x -0)-0.45
Р(х-1)-0.19
P(x-2)-0.15
Р(x-3) -0.10
P(x=4)=0.10
Find
E(X)
Oa 1.19
Ob 0.35
Oc 22
d.
Transcribed Image Text:Question 22 2 points Save Answer Let X equal the number of bits in error in the next four bits transmitted. The possible values for X are {0, 1, 2, 3, 4} Suppose that the probabilities are Р(x -0)-0.45 Р(х-1)-0.19 P(x-2)-0.15 Р(x-3) -0.10 P(x=4)=0.10 Find E(X) Oa 1.19 Ob 0.35 Oc 22 d.
Question 21
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Suppose that we have and are the sample proportions of observations in two independent random samples of sizes n = 80 , p, = 12/80 =
%3D
0.15
n2- 80 , and ,- 8/80 = 0.1 obtain an approximate 95% confidence interval on the difference in the proportion
(-0.1522 < P1-p,< 0.1432)
(0.0522 < P1-p2< 0.1477)
(-0.0522 < P1-P2 0.2522)
(-0.0522 < P1-P25 0.1522)
Transcribed Image Text:Question 21 2 points Save Answer Suppose that we have and are the sample proportions of observations in two independent random samples of sizes n = 80 , p, = 12/80 = %3D 0.15 n2- 80 , and ,- 8/80 = 0.1 obtain an approximate 95% confidence interval on the difference in the proportion (-0.1522 < P1-p,< 0.1432) (0.0522 < P1-p2< 0.1477) (-0.0522 < P1-P2 0.2522) (-0.0522 < P1-P25 0.1522)
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