(1) We select n = 50 real numbers at random and then round them off to the nearest integers, before adding them all up. Find an approximation to the probability that the difference between the sum of the rounded numbers and the sum of the original numbers is no more than 3. Solve this problem by taking the following three steps one by one. Step (i) Let Let Zı, Z2, ·… , Zn be the original numbers and let N1, N2, … ,Nn be their rounded off version. That is, for instance 13.49 and will be rounded to 13 and 13.51 will be rounded to 14. You may round up or down the number 13.50, which carries zero probability anyway. Why is it reasonable to assume that the rounding error iid U; = Z; – N; Uniform(=,), i = 1,2, .. ,n? The correct answer is CLT TTE CBS GCVF None of the above N/A (i- Select One)
(1) We select n = 50 real numbers at random and then round them off to the nearest integers, before adding them all up. Find an approximation to the probability that the difference between the sum of the rounded numbers and the sum of the original numbers is no more than 3. Solve this problem by taking the following three steps one by one. Step (i) Let Let Zı, Z2, ·… , Zn be the original numbers and let N1, N2, … ,Nn be their rounded off version. That is, for instance 13.49 and will be rounded to 13 and 13.51 will be rounded to 14. You may round up or down the number 13.50, which carries zero probability anyway. Why is it reasonable to assume that the rounding error iid U; = Z; – N; Uniform(=,), i = 1,2, .. ,n? The correct answer is CLT TTE CBS GCVF None of the above N/A (i- Select One)
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Question
![(1) We select n = 50 real numbers at random and then round them off to the nearest integers, before adding them all up.
Find an approximation to the probability that the difference between the sum of the rounded numbers and the sum of the
original numbers is no more than 3. Solve this problem by taking the following three steps one by one.
Step (i) Let Let Z1 , Z2,
for instance 13.49 and will be rounded to 13 and 13.51 will be rounded to 14. You may round up or down the number
13.50, which carries zero probability anyway. Why is it reasonable to assume that the rounding error
, Zn be the original numbers and let N1, N2, ·.. , Nn be their rounded off version. That is,
iid
U; = Z; - N; Uniform(-,), i = 1,2, ..
, n?
The correct answer is
CLT
TTE
CBS
GCVF
None of the above
N/A
(i- Select One)
Step (ii) We want to compute the probability P (| E Z¡ – E1 Ni| < 3), which is equal to
(ωP ( ΣU < 3 ) .
() P ( Σ UI 3).
(c) P (E, U; < 3).
(d) P (E, Ui 2 3).
i=1
=1
i=1
(e) None of the above
The correct answer is
(a)
(b)
(c)
(d)
(e)
N/A
(ii- Select One)
Step (iii) The desired probability of Step (ii) is approximately equal to P(|N(0, 1)| < 3/12/50) = 0.86 due to
TTV
CBS
GCVF
CLT
None of the above
N/A
(iii- Select One)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6214fda8-f992-4e88-b320-5195339361f5%2F7dcbdf0e-751e-4e6d-b504-8bfff0347d40%2F5ocy64_processed.png&w=3840&q=75)
Transcribed Image Text:(1) We select n = 50 real numbers at random and then round them off to the nearest integers, before adding them all up.
Find an approximation to the probability that the difference between the sum of the rounded numbers and the sum of the
original numbers is no more than 3. Solve this problem by taking the following three steps one by one.
Step (i) Let Let Z1 , Z2,
for instance 13.49 and will be rounded to 13 and 13.51 will be rounded to 14. You may round up or down the number
13.50, which carries zero probability anyway. Why is it reasonable to assume that the rounding error
, Zn be the original numbers and let N1, N2, ·.. , Nn be their rounded off version. That is,
iid
U; = Z; - N; Uniform(-,), i = 1,2, ..
, n?
The correct answer is
CLT
TTE
CBS
GCVF
None of the above
N/A
(i- Select One)
Step (ii) We want to compute the probability P (| E Z¡ – E1 Ni| < 3), which is equal to
(ωP ( ΣU < 3 ) .
() P ( Σ UI 3).
(c) P (E, U; < 3).
(d) P (E, Ui 2 3).
i=1
=1
i=1
(e) None of the above
The correct answer is
(a)
(b)
(c)
(d)
(e)
N/A
(ii- Select One)
Step (iii) The desired probability of Step (ii) is approximately equal to P(|N(0, 1)| < 3/12/50) = 0.86 due to
TTV
CBS
GCVF
CLT
None of the above
N/A
(iii- Select One)
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