n a certain state the proportion of families living below the poverty level is 21 %. For samples of n = 750 randomly selected families, what is the probability that the sample proportion of families that live below the poverty level is within ±0.03 from the population proportion? z= (p-π)/√(π(1-π)/n) I got an answer of 0.9566. I am not sure if it's right. Can the problem be worked out so I can better understand it?
n a certain state the proportion of families living below the poverty level is 21 %. For samples of n = 750 randomly selected families, what is the probability that the sample proportion of families that live below the poverty level is within ±0.03 from the population proportion? z= (p-π)/√(π(1-π)/n) I got an answer of 0.9566. I am not sure if it's right. Can the problem be worked out so I can better understand it?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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In a certain state the proportion of families living below the poverty level is 21 %. For samples of n = 750 randomly selected families, what is the
z= (p-π)/√(π(1-π)/n)
I got an answer of 0.9566. I am not sure if it's right. Can the problem be worked out so I can better understand it?
Expert Solution
Step 1
Solution:
Given information
n= 750 Sample size
p= 0.21 Population proportion
q= 1-p = 0.79
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