A certain rare blood type can be found in only 0.05% of people If the population of a Pandomly selected group is 3000, what is the probabilit that at least two persons in the group have this rare blood type?
A certain rare blood type can be found in only 0.05% of people If the population of a Pandomly selected group is 3000, what is the probabilit that at least two persons in the group have this rare blood type?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
Did I do this correctly? Also my professor usually wants the exact value instead of decimal points, how can I simplify it with keep the e constant, so it doesn't turn into a long decimal?
![A certain rare blood type can be found in only 0.05% of people.
If the population of a randomly selected group is 3000, what is the probabiltig
that at least two persons in the group have this rare blood type?
-2
P(N(E)=i) = C²²₂²
where 2 €3,000) (0.0005) = 1.5
C!
1-(PCX ≤ 2)) P(X<2) = P(X=0) + PCX = 1) + PCX=2)
=
e²1.5 40
O!
-1.5₁
= e
+
€¹.5 1.5¹
-1.5
e
16
+
-1.5
³+ 1.5 €7.5 + e
te
-1.5, 1.125
-1.5 1.52
2!
2
= 2.5€ ¹.5 +0.25102143
e
-0.80884683/
1-0.80884683/
= 0·19/153/69](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd60bfbb-cf96-4101-a36e-0ab8578e2904%2F0d8a22a2-8f91-45d2-a5ae-45ad768d3b02%2Fesa95r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A certain rare blood type can be found in only 0.05% of people.
If the population of a randomly selected group is 3000, what is the probabiltig
that at least two persons in the group have this rare blood type?
-2
P(N(E)=i) = C²²₂²
where 2 €3,000) (0.0005) = 1.5
C!
1-(PCX ≤ 2)) P(X<2) = P(X=0) + PCX = 1) + PCX=2)
=
e²1.5 40
O!
-1.5₁
= e
+
€¹.5 1.5¹
-1.5
e
16
+
-1.5
³+ 1.5 €7.5 + e
te
-1.5, 1.125
-1.5 1.52
2!
2
= 2.5€ ¹.5 +0.25102143
e
-0.80884683/
1-0.80884683/
= 0·19/153/69
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Recommended textbooks for you
![A First Course in Probability (10th Edition)](https://www.bartleby.com/isbn_cover_images/9780134753119/9780134753119_smallCoverImage.gif)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
![A First Course in Probability](https://www.bartleby.com/isbn_cover_images/9780321794772/9780321794772_smallCoverImage.gif)
![A First Course in Probability (10th Edition)](https://www.bartleby.com/isbn_cover_images/9780134753119/9780134753119_smallCoverImage.gif)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
![A First Course in Probability](https://www.bartleby.com/isbn_cover_images/9780321794772/9780321794772_smallCoverImage.gif)