Question 2 (Repeated Eigenvalues x' 1 Solve 15 x(0) 5+2t x(t = 2 +t - e3t +2e2t – 12t – 7] 2e3t – 2e2t + 6t +5 71 x(t): x(t) = 42 5lat 2.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Question 2 (Repeated Eigenvalues).
x'
Solve
x(0)
5+2t
x(t =
2 +t
- e3t +2e2t – 12t – 7]
x(t):
[ 2e3t – 2e2t + 6t + 5
x(t) = 42
x(t) =
let
[ 5-t
x(t) =
[ 2 +t]
e3t - 2e2t – 11t – 5
x(t) = -2e3t + 2e2t + 7t+5
5+ 5t
x(t) =
2 +2t
13t – 6
x(t):
t+5
e3t - 2e2t – 11t - 6
x(t) = -23t + 2e2t + 7t +5.
- e3t +2e2t – 12t -6
x(t) = 23t - 2e²t +6t + 5
Transcribed Image Text:Question 2 (Repeated Eigenvalues). x' Solve x(0) 5+2t x(t = 2 +t - e3t +2e2t – 12t – 7] x(t): [ 2e3t – 2e2t + 6t + 5 x(t) = 42 x(t) = let [ 5-t x(t) = [ 2 +t] e3t - 2e2t – 11t – 5 x(t) = -2e3t + 2e2t + 7t+5 5+ 5t x(t) = 2 +2t 13t – 6 x(t): t+5 e3t - 2e2t – 11t - 6 x(t) = -23t + 2e2t + 7t +5. - e3t +2e2t – 12t -6 x(t) = 23t - 2e²t +6t + 5
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