Question 18: Combinatorics - Pigeonhole Principle Applications Instructions: Use data from the link provided below and make sure to give your original work. Plagiarism will not be accepted. You can also use different colors and notations to make your work clearer and more visually appealing. Problem Statement: Prove that in any group of 367 people, at least two people share the same birthday. Theoretical Parts: 1. Pigeonhole Principle Statement: State the Pigeonhole Principle and provide simple examples illustrating its use. 2. Application to Birthdays: Explain how the Pigeonhole Principle applies to the problem of shared birthdays in a group. 3. Proof: Using the Pigeonhole Principle, prove that in any group of 367 people, at least two must share the same birthday, assuming there are only 366 possible birthdays (including February 29). Data Link: https://drive.google.com/drive/folders/1G8h19jKIMnOpQrStUvWxYz23456EFG
Question 18: Combinatorics - Pigeonhole Principle Applications Instructions: Use data from the link provided below and make sure to give your original work. Plagiarism will not be accepted. You can also use different colors and notations to make your work clearer and more visually appealing. Problem Statement: Prove that in any group of 367 people, at least two people share the same birthday. Theoretical Parts: 1. Pigeonhole Principle Statement: State the Pigeonhole Principle and provide simple examples illustrating its use. 2. Application to Birthdays: Explain how the Pigeonhole Principle applies to the problem of shared birthdays in a group. 3. Proof: Using the Pigeonhole Principle, prove that in any group of 367 people, at least two must share the same birthday, assuming there are only 366 possible birthdays (including February 29). Data Link: https://drive.google.com/drive/folders/1G8h19jKIMnOpQrStUvWxYz23456EFG
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 52E
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