Exercise Determine whether the equation is exact. If it is, solve it. If it is not, find an integrating factor to make it exact and then solve the equation: 2xy dx + (x² - 1) dy = 0. dy xy²-cos x sin x dx = y(1-x2) with y(0) = 2. xy dx + (2x² + 3y² = 20) dy = 0. xdx+(x²y+4y) dy = 0, with y(4) = 0. Plot of y²(1 - x²) — cos² x = 3, solution to second problem.

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 27PT: Find the unknown value. 27. y varies jointly with x and the cube root of 2. If when x=2 and...
Question
not use ai please
Exercise
Determine whether the equation is exact. If it is, solve it. If it is not, find an
integrating factor to make it exact and then solve the equation:
2xy dx + (x² - 1) dy = 0.
dy xy²-cos x sin x
dx
=
y(1-x2)
with y(0) = 2.
xy dx + (2x² + 3y² = 20) dy = 0.
xdx+(x²y+4y) dy = 0, with y(4) = 0.
Plot of y²(1 - x²) — cos² x = 3,
solution to second problem.
Transcribed Image Text:Exercise Determine whether the equation is exact. If it is, solve it. If it is not, find an integrating factor to make it exact and then solve the equation: 2xy dx + (x² - 1) dy = 0. dy xy²-cos x sin x dx = y(1-x2) with y(0) = 2. xy dx + (2x² + 3y² = 20) dy = 0. xdx+(x²y+4y) dy = 0, with y(4) = 0. Plot of y²(1 - x²) — cos² x = 3, solution to second problem.
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