Question 14 of 31 How many grams of nitric acid , HNO3, are required to neutralize (completely react with) 4.30 g of Ca(OH)2 according to the acid-base reaction: 2 HNO3(aq) + Ca(OH)2(aq) 2 H20(1) + Ca(NO3)2(aq) 1 molCafOH)2 molHNO, g Ca(OH)2 63.02 7.31 g HNO, 74.10 gCafeHTE molCatOH)2 1 1 molHNO, H)2 2 mol HNO3 63.02 g Ca(OH)2 = 7.31 g HNO3 H)2 1 mol Ca(OH)2 1 mol HNO3 ADD FACTOR DELETE ANSWER RESET *( ) 7.31 4.30 0.0580 63.02 74.10 3.60 18.02 0.0682 0.116 6.022 x 102 1 164.10 g Ca(NO,)2 g H20 mol Ca(NO3)2 g Ca(OH)2 mol H2O mol HNO3 mol Ca(OH)2 g HNO,
Question 14 of 31 How many grams of nitric acid , HNO3, are required to neutralize (completely react with) 4.30 g of Ca(OH)2 according to the acid-base reaction: 2 HNO3(aq) + Ca(OH)2(aq) 2 H20(1) + Ca(NO3)2(aq) 1 molCafOH)2 molHNO, g Ca(OH)2 63.02 7.31 g HNO, 74.10 gCafeHTE molCatOH)2 1 1 molHNO, H)2 2 mol HNO3 63.02 g Ca(OH)2 = 7.31 g HNO3 H)2 1 mol Ca(OH)2 1 mol HNO3 ADD FACTOR DELETE ANSWER RESET *( ) 7.31 4.30 0.0580 63.02 74.10 3.60 18.02 0.0682 0.116 6.022 x 102 1 164.10 g Ca(NO,)2 g H20 mol Ca(NO3)2 g Ca(OH)2 mol H2O mol HNO3 mol Ca(OH)2 g HNO,
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Question 14 of 31
How many grams of nitric acid, HNO3, are required to neutralize (completely react
with) 4.30 g of Ca(OH)2 according to the acid-base reaction:
HNO3(aq) + Ca(OH)2(aq) –
2 H20(1) + Ca(NO3)2(aq)
->
1
moLCatOH)2
molHINO;
63.02
g Ca(OH)2
7.31
g HNO3
74.10
1
moLCatOH),
1
molHNO;
H)2
2 mol HNO3
63.02 g Ca(OH)2
= 7.31 g HNO3
OH)2
1 mol Ca(OH)2
1 mol HNO3
ADD FACTOR
DELETE
ANSWER
RESET
()
%3D
3.60
18.02
2
7.31
4.30
0.0580
63.02
74.10
0.0682
0.116
6.022 x 1023
1
164.10
mol H2O
g Ca(NO3)2
g H20
mol Ca(NO3)2 g Ca(OH)2
mol HNO3
mol Ca(OH)2
g HNO3
I|
2]
2]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F40a9514d-d7ca-4467-8320-3b6e9b54f257%2F0bdfa711-9ffe-415b-8e25-c1833301eb4a%2Fmbc3k2m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 14 of 31
How many grams of nitric acid, HNO3, are required to neutralize (completely react
with) 4.30 g of Ca(OH)2 according to the acid-base reaction:
HNO3(aq) + Ca(OH)2(aq) –
2 H20(1) + Ca(NO3)2(aq)
->
1
moLCatOH)2
molHINO;
63.02
g Ca(OH)2
7.31
g HNO3
74.10
1
moLCatOH),
1
molHNO;
H)2
2 mol HNO3
63.02 g Ca(OH)2
= 7.31 g HNO3
OH)2
1 mol Ca(OH)2
1 mol HNO3
ADD FACTOR
DELETE
ANSWER
RESET
()
%3D
3.60
18.02
2
7.31
4.30
0.0580
63.02
74.10
0.0682
0.116
6.022 x 1023
1
164.10
mol H2O
g Ca(NO3)2
g H20
mol Ca(NO3)2 g Ca(OH)2
mol HNO3
mol Ca(OH)2
g HNO3
I|
2]
2]
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