Question 14 of 31How many grams of nitric acid, HNO3, are required to neutralize (completely reactwith) 4.30 g of Ca(OH)2 according to the acid-base reaction:HNO3(aq) + Ca(OH)2(aq) –2 H20(1) + Ca(NO3)2(aq)->1moLCatOH)2molHINO;63.02g Ca(OH)27.31g HNO374.101moLCatOH),1molHNO;H)22 mol HNO363.02 g Ca(OH)2= 7.31 g HNO3OH)21 mol Ca(OH)21 mol HNO3ADD FACTORDELETEANSWERRESET()%3D3.6018.0227.314.300.058063.0274.100.06820.1166.022 x 10231164.10mol H2Og Ca(NO3)2g H20mol Ca(NO3)2 g Ca(OH)2mol HNO3mol Ca(OH)2g HNO3I|2]2]

Answered: Image /qna-images/answer/0bdfa711-9ffe-415b-8e25-c1833301eb4a.jpg

Question 14 of 31 How many grams of nitric acid , HNO3, are required to neutralize (completely react with) 4.30 g of Ca(OH)2 according to the acid-base reaction: 2 HNO3(aq) + Ca(OH)2(aq) 2 H20(1) + Ca(NO3)2(aq) 1 molCafOH)2 molHNO, g Ca(OH)2 63.02 7.31 g HNO, 74.10 gCafeHTE molCatOH)2 1 1 molHNO, H)2 2 mol HNO3 63.02 g Ca(OH)2 = 7.31 g HNO3 H)2 1 mol Ca(OH)2 1 mol HNO3 ADD FACTOR DELETE ANSWER RESET *( ) 7.31 4.30 0.0580 63.02 74.10 3.60 18.02 0.0682 0.116 6.022 x 102 1 164.10 g Ca(NO,)2 g H20 mol Ca(NO3)2 g Ca(OH)2 mol H2O mol HNO3 mol Ca(OH)2 g HNO,

Question 14 of 31 How many grams of nitric acid , HNO3, are required to neutralize (completely react with) 4.30 g of Ca(OH)2 according to the acid-base reaction: 2 HNO3(aq) + Ca(OH)2(aq) 2 H20(1) + Ca(NO3)2(aq) 1 molCafOH)2 molHNO, g Ca(OH)2 63.02 7.31 g HNO, 74.10 gCafeHTE molCatOH)2 1 1 molHNO, H)2 2 mol HNO3 63.02 g Ca(OH)2 = 7.31 g HNO3 H)2 1 mol Ca(OH)2 1 mol HNO3 ADD FACTOR DELETE ANSWER RESET *( ) 7.31 4.30 0.0580 63.02 74.10 3.60 18.02 0.0682 0.116 6.022 x 102 1 164.10 g Ca(NO,)2 g H20 mol Ca(NO3)2 g Ca(OH)2 mol H2O mol HNO3 mol Ca(OH)2 g HNO,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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