Question 13 15 mol of AB(g) is placed in an empty 1,0 dm container. Equilibrium is reached at 500 K after 6 minutes. 2 AB(g) = A2(g) + B2(g) There is 5,0 mol B2(g) in the reaction mixture at equilibrium. 13.1 Calculate: 13.1.1 the concentration of each substance at equilibrium.

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Question 13
15 mol of AB(g) is placed in an empty 1,0 dm
container. Equilibrium is reached at 500 K after
6 minutes.
2 AB(g)
A2(g) + B2(g)
There is 5,0 mol B2(g) in the reaction mixture at
equilibrium.
13.1 Calculate:
13.1.1 the concentration of each substance
at equilibrium.
Transcribed Image Text:Question 13 15 mol of AB(g) is placed in an empty 1,0 dm container. Equilibrium is reached at 500 K after 6 minutes. 2 AB(g) A2(g) + B2(g) There is 5,0 mol B2(g) in the reaction mixture at equilibrium. 13.1 Calculate: 13.1.1 the concentration of each substance at equilibrium.
13.1.2 the equilibrium constant (Kc) at 500 K.
13.2 The temperature is increased to 800 K after
12 minutes. The forward reaction is favoured
more than the reverse reaction. A new
equilibrium is reached after 18 minutes.
13.2.1 Draw a graph of reaction rate against
time on which you show all changes to
the rate over the 18 minutes.
13.2.2 Is the forward reaction exothermic or
endothermic? Explain.
13.2.3 How will the Ke value change at the
new temperature of 800 K?
Transcribed Image Text:13.1.2 the equilibrium constant (Kc) at 500 K. 13.2 The temperature is increased to 800 K after 12 minutes. The forward reaction is favoured more than the reverse reaction. A new equilibrium is reached after 18 minutes. 13.2.1 Draw a graph of reaction rate against time on which you show all changes to the rate over the 18 minutes. 13.2.2 Is the forward reaction exothermic or endothermic? Explain. 13.2.3 How will the Ke value change at the new temperature of 800 K?
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