Nitrogen dioxide dimerizes according to the following reaction: 2 NO₂ (9) K₂= 6.7 at 298 K N₂O4 (9) A 2.25-L container contains 0.055 mol of NO₂ and 0.082 mol of N₂O4 at 298 K. Part A Is the reaction at equilibrium? If not, in what direction will the reaction proceed? O The reaction is at equilibrium. The reaction is not at equilibrium and will shift to the left. The reaction is not at equilibrium and will shift to the right.
Nitrogen dioxide dimerizes according to the following reaction: 2 NO₂ (9) K₂= 6.7 at 298 K N₂O4 (9) A 2.25-L container contains 0.055 mol of NO₂ and 0.082 mol of N₂O4 at 298 K. Part A Is the reaction at equilibrium? If not, in what direction will the reaction proceed? O The reaction is at equilibrium. The reaction is not at equilibrium and will shift to the left. The reaction is not at equilibrium and will shift to the right.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![Nitrogen dioxide dimerizes according to the
following reaction:
2 NO₂ (9)
K₂ = 6.7 at 298 K
N₂O4 (9)
A 2.25-L container contains 0.055 mol of NO₂
and 0.082 mol of N₂O4 at 298 K.
Part A
Is the reaction at equilibrium? If not, in what direction will the reaction proceed?
The reaction is at equilibrium.
The reaction is not at equilibrium and will shift to the left.
The reaction is not at equilibrium and will shift to the right.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe49f0939-1d27-41de-9007-a1b394fa79d1%2Facfcb0d9-e5d1-4d35-ab0c-70ea1d736191%2Fo3py7bj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Nitrogen dioxide dimerizes according to the
following reaction:
2 NO₂ (9)
K₂ = 6.7 at 298 K
N₂O4 (9)
A 2.25-L container contains 0.055 mol of NO₂
and 0.082 mol of N₂O4 at 298 K.
Part A
Is the reaction at equilibrium? If not, in what direction will the reaction proceed?
The reaction is at equilibrium.
The reaction is not at equilibrium and will shift to the left.
The reaction is not at equilibrium and will shift to the right.
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