Question 1. Convert the following code into assembly language program while (BX <- X) BX = BX + 2; X =X + 1;
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![Formative Lab Assessment 3
Question 1.
Convert the following code into assembly language program
while (BX <- X)
BX = BX + 2;
%3D
X =X + 1;
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- Don't reject if you did not have knowledge. Assembly language. On sim8085 simulatortranslate the following c program into pep/9 assembly languagePlease can you convert this part of a c program to pep 9 assembly language void findLog ( int *result, int num, int b ) { int k; num--; *result = 0; while (num > 0) { *result = *result + 1; num = divide(num, b); } // end while } // end of findLog( )
- change to ada language import java.util.scanner; public class problem41 { public static void main(string[] args) { scanner input = new scanner(system.in); int positives = 0; // count the number of positive numbers int negatives = 0; // count the number of negative numbers int count = 0; // count all numbers double total = 0; // accumulate a totol // promopt the user to enter an integer or 0 to exit system.out.print("enter an integer, the input ends if it is 0: "); int number = input.nextint(); if (number == 0) { // test for sentinel value system.out.println("no numbers are entered except 0"); system.exit(1); } while (number != 0) {// test for sentinel value if (number > 0) { positives++; // increase positives } else { negatives++; // increase negatives } total += number; // accumulate total count++; // increase the count number = input.nextint();//read the next number } // calculate the average double average = total / count; // display results system.out.println( "the number of…Program the following in C language. Implement the following equation 3x4sin(180x) + 4x3 cos(90x) + x2sin(tan(45)) + 7x + 9cos(90x2 )where x may be user defined value.Convert the following c++ code into pep9 assembly language #include <iostream> using namespace std; int times(int mpr, int mcand) { int prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } return prod; } int main(){ int n, m; cout << "Enter two numbers: "; cin >> n >> m; cout << "Product: " << times(n, m) << endl; return 0; } Submit: pep source code and as well as the screenshot of pep9 assembly code running in the pep stimulator.
- in openglExample: The Problem Input File Using C programming language write a program that simulates a variant of the Tiny Machine Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the Tiny Machine Architecture: //IN 5 //OUT 7 //STORE O //IN 5 //OUT 7 //STORE 1 //LOAD O //SUB 1 55 67 30 55 67 1 LOAD 2- ADD 3> STORE 4> SUB 5> IN 6> OUT 7> END 8> JMP 9> SKIPZ 31 10 41 30 //STORE O 67 //OUT 7 11 /LOAD 1 //OUT 7 //END 67 70 Output Specifications Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Memory Address Registers, Instruction Memory, Data Memory, Memory Data Registers, and Accumulator). Data Memory will be represented by an integer array. Your Program Counter will begin pointing to the first instruction of the program. Your simulator should provide output according to the input file. Along with…You are hired by CurryPapa company to design a curry puff vending machine controller. The price of a curry puff is 30¢. The machine has a single coin slot that only accepts 10¢ and 20¢ coins. The size of the coin slot is designed such that only one coin can be inserted at a time. A mechanical sensor indicates whether a 10¢ coin or a 20¢ coin has been inserted into the coin slot. The machine delivers a curry puff to the customer after it has received total 30¢ coins. If the machine received total 40¢ coins, it delivers a curry puff and returns a 10¢ coin as the change. (b) The company also asked you to design the vending machine controller using Verilog. Complete the Verilog module in Appendix B by writing proper codes in the empty boxes.
- Convert the following c++ code into pep9 assembly language #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; }Translate the following C program to Pep/9 assembly language. #include <stdio.h> int myAge; void putNext(int age) {int nextYr;nextYr = age + 1;printf("Age: %d\n", age);printf("Age next year: %d\n", nextYr);} int main () {scanf("%d", &myAge);putNext(myAge);putNext(64);return 0;}Convert the following into Pep/9 Assembler: #include using namespace std; int square(int n){ int i; int sq; sq = 0; for (i = 0; i < n; i++){ sq = sq + n; } return sq; } int main (){ int num; cout << "Enter a number: "; cin >> num; cout << num << " squared = " << square(num) << endl; return 0; }
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