Question 1: The load is supported by the four 304 stainless stell wires that are connected to the rigid members AB and DC. Determine the angle of tilt of each member after the C (Newton)load is applied. The members were originally horizontal, and each wire has a cross-sectional area of 15 mm?. E304=193 Gpa E Take: A= 1.8 m meter B= 2.8 m C= 2503 N B meter |0.5 m 1 m 0.9 m B -0.5 m| 1.5 m Solution: E E Z
Question 1: The load is supported by the four 304 stainless stell wires that are connected to the rigid members AB and DC. Determine the angle of tilt of each member after the C (Newton)load is applied. The members were originally horizontal, and each wire has a cross-sectional area of 15 mm?. E304=193 Gpa E Take: A= 1.8 m meter B= 2.8 m C= 2503 N B meter |0.5 m 1 m 0.9 m B -0.5 m| 1.5 m Solution: E E Z
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.4.9P: Two steel wines support a moveable overhead camera weighing W = 28 lb (see figure part a) used For...
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![Question 1:
The load is supported by the four 304 stainless stell wires that are connected to the rigid members
AB and DC. Determine the angle of tilt of each member after the C (Newton) load is applied.
The members were originally horizontal, and each wire has a cross-sectional area of 15 mm?.
E304=193 Gpa
G
Take:
A=
1.8
m
A
meter
B=
2.8
m
C=
2503
N
B meter
H
D
|0.5 m
1 m
0.9 m
- 0.5 m|
1.5 m
C N
Solution:
0.5m
lm
FDE
FCF
0.5 m
1 m
Päge-1
1.5m
FAH
0.5m
to
0.5 m
Internal Forces in the wires :
EM, = 0; 2FRG -C(1.5)=0
УF, 3D 0; Fан + Fва — С%3D0
F,
FBG
N
A
FAH =
N
FCF
EM, = 0; 1.5Fcr -0.5FH = 0
EF, = 0; FDE + FeF – FAH = 0
FDE
N
Displacement :
8,
тт
FeLCF
8c =
тт
AcE
тт
1
1.5
8, = 8 +8c =
тm
tan a =
a
• Ans
1500
FAHLAH
A AE
O ALH =
тт
8 = 8µ+84H =
тm
FBGLBG
8, =
тт
ABGE
tan B =
B =
Ans
2000
I| ||
I| ||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33021eb5-2bd3-494a-8fcb-ef0877ddbaad%2F801cb570-d23a-494c-a7d3-7e737fb2365e%2Ffgefhko_processed.png&w=3840&q=75)
Transcribed Image Text:Question 1:
The load is supported by the four 304 stainless stell wires that are connected to the rigid members
AB and DC. Determine the angle of tilt of each member after the C (Newton) load is applied.
The members were originally horizontal, and each wire has a cross-sectional area of 15 mm?.
E304=193 Gpa
G
Take:
A=
1.8
m
A
meter
B=
2.8
m
C=
2503
N
B meter
H
D
|0.5 m
1 m
0.9 m
- 0.5 m|
1.5 m
C N
Solution:
0.5m
lm
FDE
FCF
0.5 m
1 m
Päge-1
1.5m
FAH
0.5m
to
0.5 m
Internal Forces in the wires :
EM, = 0; 2FRG -C(1.5)=0
УF, 3D 0; Fан + Fва — С%3D0
F,
FBG
N
A
FAH =
N
FCF
EM, = 0; 1.5Fcr -0.5FH = 0
EF, = 0; FDE + FeF – FAH = 0
FDE
N
Displacement :
8,
тт
FeLCF
8c =
тт
AcE
тт
1
1.5
8, = 8 +8c =
тm
tan a =
a
• Ans
1500
FAHLAH
A AE
O ALH =
тт
8 = 8µ+84H =
тm
FBGLBG
8, =
тт
ABGE
tan B =
B =
Ans
2000
I| ||
I| ||
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