Question 1:The load is supported by the four 304 stainless stell wires that are connected to the rigid membersAB and DC. Determine the angle of tilt of each member after the C (Newton) load is applied.The members were originally horizontal, and each wire has a cross-sectional area of 15 mm?.E304=193 GpaGTake:A=1.8mAmeterB=2.8mC=2503NB meterHD|0.5 m1 m0.9 m- 0.5 m|1.5 mC NSolution:0.5mlmFDEFCF0.5 m1 mPäge-11.5mFAH0.5mto0.5 mInternal Forces in the wires :EM, = 0; 2FRG -C(1.5)=0УF, 3D 0; Fан + Fва — С%3D0F,FBGNAFAH =NFCFEM, = 0; 1.5Fcr -0.5FH = 0EF, = 0; FDE + FeF – FAH = 0FDENDisplacement :8,ттFeLCF8c =ттAcEтт11.58, = 8 +8c =тmtan a =a• Ans1500FAHLAHA AEO ALH =тт8 = 8µ+84H =тmFBGLBG8, =ттABGEtan B =B =Ans2000I| ||I| ||

To determine the angle of tilt.

Question 1: The load is supported by the four 304 stainless stell wires that are connected to the rigid members AB and DC. Determine the angle of tilt of each member after the C (Newton)load is applied. The members were originally horizontal, and each wire has a cross-sectional area of 15 mm?. E304=193 Gpa E Take: A= 1.8 m meter B= 2.8 m C= 2503 N B meter |0.5 m 1 m 0.9 m B -0.5 m| 1.5 m Solution: E E Z

Question 1: The load is supported by the four 304 stainless stell wires that are connected to the rigid members AB and DC. Determine the angle of tilt of each member after the C (Newton)load is applied. The members were originally horizontal, and each wire has a cross-sectional area of 15 mm?. E304=193 Gpa E Take: A= 1.8 m meter B= 2.8 m C= 2503 N B meter |0.5 m 1 m 0.9 m B -0.5 m| 1.5 m Solution: E E Z

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.4.9P: Two steel wines support a moveable overhead camera weighing W = 28 lb (see figure part a) used For...

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Question 1: The load is supported by the four 304 stainless stell wires that are connected to the rigid members AB and DC. Determine the angle of tilt of each member after the C (Newton) load is applied. The members were originally horizontal, and each wire has a cross-sectional area of 15 mm. E30-=193 Gpa E G Take: A= 1 m A meter B= m C= 2495 N B meter |0.5 m 1 m 0.9 m 1.5 m -0.5 m C N Solution: 0.5m Im F 0.5 m 1m 1.5m 0.5m AM rage 4 1.5m 0.5 m Intemal Forces in the wires : EM, -0; 2F -C(1.5)=0 EF, = 0; F +F., -C = 0 N F N EM, -0; 1.5F, -0.5F,, =0 EF, = 0; Fm +Fa -F =0 Fer= FrE N
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