QUESTION 1 Sodium bicarbonate (NaHCO3) dissolves in water by the following reaction: NaHCO3 (s) + Na* (aq) + HCO3 (aq) K = 1.3 When dissolved in 100 ml of pure water, equilibrium is achieved when 9.6 g NaHCO3 is added. I then try to dissolve NaHCO3 in other aqueous solutions. Which solution will achieve equilibrium with the least amount of NaHCOz added? O 1.0 M NaCI O 1.0 M KCI O 1.0 M KI QUESTION 2 I want to make a pH buffer with a pH of 9.5. From the following given pka and pkh values, which mixture would be best to do so? (Henderson-Hasselbalch equation: pH = pka + log([base)[acid])) Benzoic acid (C6H5COOH): pKka = 4.19 Pyridine (C5H5N): pKh = 8.77 Ammonia (NH3): pKp = 4.75 1.1 M C5H5N and 0.20 M C5H5NH* O 0.60 M C5H5N 0.50 M C6H5COOH and 1.0 M C6H5C" 0.80 M NH3 and 0.45 M NHA+
QUESTION 1 Sodium bicarbonate (NaHCO3) dissolves in water by the following reaction: NaHCO3 (s) + Na* (aq) + HCO3 (aq) K = 1.3 When dissolved in 100 ml of pure water, equilibrium is achieved when 9.6 g NaHCO3 is added. I then try to dissolve NaHCO3 in other aqueous solutions. Which solution will achieve equilibrium with the least amount of NaHCOz added? O 1.0 M NaCI O 1.0 M KCI O 1.0 M KI QUESTION 2 I want to make a pH buffer with a pH of 9.5. From the following given pka and pkh values, which mixture would be best to do so? (Henderson-Hasselbalch equation: pH = pka + log([base)[acid])) Benzoic acid (C6H5COOH): pKka = 4.19 Pyridine (C5H5N): pKh = 8.77 Ammonia (NH3): pKp = 4.75 1.1 M C5H5N and 0.20 M C5H5NH* O 0.60 M C5H5N 0.50 M C6H5COOH and 1.0 M C6H5C" 0.80 M NH3 and 0.45 M NHA+
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![QUESTION 1
Sodium bicarbonate (NaHCO3) dissolves in water by the following reaction:
NaHCO3 (s) - Na* (aq) + HCO3 (aq)
Ke = 1.3
When dissolved in 100 ml of pure water, equilibrium is achieved when 9.6 g NaHCO3 is added. I then try to dissolve NaHCO3 in other aqueous solutions. Which solution will achieve equilibrium with the least
amount of NaHCO3 added?
O 1.0 M NaCl
O 1.0 M KCI
O 1.0 M KI
QUESTION 2
I want to make a pH buffer with a pH of 9.5.
From the following given pka and pkh values, which mixture would be best to do so?
(Henderson-Hasselbalch equation: pH = pka + log([base)[acid]))
Benzoic acid (CGH5COOH): pka = 4.19
Pyridine (C5H5N): pKb = 8.77
Ammonia (NH3): pkh = 4.75
1.1 M C5H5N and 0.20 M C5H5NH*
O 0.60 M C5H5N
O 0.50 M C6H5COOH and 1.0 M C6H5C0
0.80 M NH3 and 0.45 M NH4+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3514cb9c-eb0f-42f6-abe9-52d5625a050c%2F3f9c1a8d-d1d9-43ce-95e2-6eab21874947%2Fmk5szqf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 1
Sodium bicarbonate (NaHCO3) dissolves in water by the following reaction:
NaHCO3 (s) - Na* (aq) + HCO3 (aq)
Ke = 1.3
When dissolved in 100 ml of pure water, equilibrium is achieved when 9.6 g NaHCO3 is added. I then try to dissolve NaHCO3 in other aqueous solutions. Which solution will achieve equilibrium with the least
amount of NaHCO3 added?
O 1.0 M NaCl
O 1.0 M KCI
O 1.0 M KI
QUESTION 2
I want to make a pH buffer with a pH of 9.5.
From the following given pka and pkh values, which mixture would be best to do so?
(Henderson-Hasselbalch equation: pH = pka + log([base)[acid]))
Benzoic acid (CGH5COOH): pka = 4.19
Pyridine (C5H5N): pKb = 8.77
Ammonia (NH3): pkh = 4.75
1.1 M C5H5N and 0.20 M C5H5NH*
O 0.60 M C5H5N
O 0.50 M C6H5COOH and 1.0 M C6H5C0
0.80 M NH3 and 0.45 M NH4+
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