Question (1) Find the output of the following program: public class myPoint ( private int x; private int y; private static int count=0; public myPoint (int a, int b) { x=a; y=b; count++; } 6 20 public myPoint ( ) { x=0;y=0; count++; } public void add () { x=x+y; } public void add (int a) { x=y+a; count--;} public static int getCount() { return count; }-2 public int getX() { return x; } public int getY() { return y; } V=20 x 1 y 2 public class itemDemo { public static void main(String args[]) ( myPoint Pl=new myPoint (10,20); myPoint P2=new myPoint (1, 2); ✓o System.out.println (P1.getX()); System.out.println (P2.getX()); }// end of class 2-int M P1.getCount (); System.out.println (M); P1. add (M); System.out.println (P1.getX()); < 10-201 System.out.println (P2 getX()); System.out.println (P2.getCount()); E
Question (1) Find the output of the following program: public class myPoint ( private int x; private int y; private static int count=0; public myPoint (int a, int b) { x=a; y=b; count++; } 6 20 public myPoint ( ) { x=0;y=0; count++; } public void add () { x=x+y; } public void add (int a) { x=y+a; count--;} public static int getCount() { return count; }-2 public int getX() { return x; } public int getY() { return y; } V=20 x 1 y 2 public class itemDemo { public static void main(String args[]) ( myPoint Pl=new myPoint (10,20); myPoint P2=new myPoint (1, 2); ✓o System.out.println (P1.getX()); System.out.println (P2.getX()); }// end of class 2-int M P1.getCount (); System.out.println (M); P1. add (M); System.out.println (P1.getX()); < 10-201 System.out.println (P2 getX()); System.out.println (P2.getCount()); E
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Concept explainers
OOPs
In today's technology-driven world, computer programming skills are in high demand. The object-oriented programming (OOP) approach is very much useful while designing and maintaining software programs. Object-oriented programming (OOP) is a basic programming paradigm that almost every developer has used at some stage in their career.
Constructor
The easiest way to think of a constructor in object-oriented programming (OOP) languages is:
Question
![Question (1) Find the output of the following program:
public class myPoint {
private int x;
private int y;
private static int count=0;
public myPoint (int a, int b)
{ x=a; y=b; count++; }
1
20
public myPoint ( )
{ x=0;y=0; count++; }
public void add ()
{ x=x+y; }
public void add (int a)
{ x=y+a; count--; }
public static int getCount()
{ return count; }-2
public int getX()
{ return x; }
public int getY()
{ return y; }
K
V=20
P2
x 1
y
}// end of class
2
M
public class itemDemo {
public static void main(String args[])
{
myPoint Pl=new myPoint (10,20);
myPoint P2=new myPoint (1, 2);
✓o System.out.println (P1.getX());
System.out.println (P2.getX());
2-int M = P1.getCount ();
System.out.println (M);
P1. add (M);
System.out.println (P1.getX()); <20+0
o to
System.out.println (P2 getX());
System.out.println (P2.getCount());](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F803b8012-1ec0-4227-a2e8-49a144b25cf3%2F826ad990-2273-49ec-bb4d-ea10ed1be065%2Fm5l5sqa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question (1) Find the output of the following program:
public class myPoint {
private int x;
private int y;
private static int count=0;
public myPoint (int a, int b)
{ x=a; y=b; count++; }
1
20
public myPoint ( )
{ x=0;y=0; count++; }
public void add ()
{ x=x+y; }
public void add (int a)
{ x=y+a; count--; }
public static int getCount()
{ return count; }-2
public int getX()
{ return x; }
public int getY()
{ return y; }
K
V=20
P2
x 1
y
}// end of class
2
M
public class itemDemo {
public static void main(String args[])
{
myPoint Pl=new myPoint (10,20);
myPoint P2=new myPoint (1, 2);
✓o System.out.println (P1.getX());
System.out.println (P2.getX());
2-int M = P1.getCount ();
System.out.println (M);
P1. add (M);
System.out.println (P1.getX()); <20+0
o to
System.out.println (P2 getX());
System.out.println (P2.getCount());
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