Questic Assuming a constant-voltage diode model for identical diodes D1, and D2, plot Vout as a function of Vin for the circuit shown below. R1 1 ΚΩ Vout Vou D2 La حبة D₁ Vin WK итер Vin's
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- How is a solid-state diode tested? Explain.Consider a junction diode has dc biased current at operating point ID=0.8 mA. A sinusoidal voltage is superimposed on the VD such that the peak-to-peak sinusoidal current id(t) = 0.05ID. Find the value of the applied peak-to-peak sinusoidal voltage vd(t).Determine which diodes are forward-biased and which are reverse-biased in the configurations.. Assuming a 0.7-V drop across each forward-biased diode, determine the output voltage.
- consider the figure below that shows an approximated reverse recovery turn-off characteristics for a power diode. Show that the following relation can express the total reverse recovery charge, Qrr = 1/2(trr*ts1) di1/dt =1/2(trr*ts21) di2/dt * ip Isl 1s2! -IrFor the given circuit, assume the diode D1 and D2 are the ideal diodes. The average value of the voltage Vab (in volts) across the terminal A and B isPlease solve the problem
- Please respond to question in attached image. Please.Question 1: In the circuit shown below, the output (Vo = 10V Max.) Unipolar. The frequency of Primary is 60 Hz. The diodes are Silicon with VD = 0.7V. a. Sketch the output without a Capacitor. b. Determine Voc without a Capacitor. c. Sketch Vs (at the Secondary). d. Determine Voc with a Capacitor of 10 uF across RL. e. Determine the RMS Value of Vp (at the Primary). f. PIV (Peak Inverse Voltage). 10:1 Output C. 22 k1 All diodes are IN4001. | 00000Please can you help with question B
- 4. Assume the Blue LED has a forward turn on voltage of 4 V and exhibits ideal diode behavior. For the circuit below, sketch the voltage across the diode and the voltage across the resistor (versus time) for the following Vin values. On your waveforms, indicate the time periods when the LED is on. a. Vin= 3 sin(2π *60t) V b. Vin = 5 sin(2π *60t) V Blue LED # Vin 1k R2Can someone explain this problem step by step, pleaseGiven the following circuit with VDD= 9.2 V, R=2.3 k2, then the current Iis: Use the CVD model for the diode, with VD = 0.65 V. I VDD a. 0.004000 A O b. 3.717391 A OC. 0 A d. 4.000000 A e. 0.003717 A R + VD -