Quarter-circle WATER Hinge

Q: The three bars are made of steel and form a pin-connected truss. Each bar has a cross sectional area…

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Q: Determine the member force CD (kN) shown in the figure. B 3 kN 2 m 45° A 30 30 2 m 2 m

A: Given data in question  Truss  Loading Span member length  To find out  Member force in CD

Q: 6. A 100 N force acts along 10 points the line AB, as shown in the figure below. Determine the…

A: Consider the given figure  Given data F=100 NL=20 mmB=20 mmL and B are length and breath of the…

Q: 0.12 For the portal frame shown in the given figure, the shear equation is P B 4 m 4 m EI = Constant…

A: From, given portal frame, We need to determine shear equation.

Q: The cross section of a slit rectangular tube ofconstant thickness is shown in the figures.(a) Derive…

A: in the given question the basic data that is the length and width and thickness of web and flenge…

Q: Determine the internal forces at point J for the structure shown, where member BD can only carry…

A: Given:- a=160 mmP=450 N To find:- Internal force at point J

Q: 5. A rigid bar AB, 9 m long is suspended by two vertical rods at its end A and B and hangs in a…

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Q: 11. Refer to figure 5. The links of the chain are made of steel that has a working stress of 300 MPa…

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Q: 1) A two pinned end bars AB (Copper), A= 850 mm², E = 120 GPa and BC (Aluminum), A= 1000mm² , E = 70…

A: To find out the horizontal displacement of pin B.

Q: A = 2000 mm² A = 900 mm² B 503 mm 257 mm 355 mm The steel rod is stress-free before the axial loads…

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Q: Question 10 1 2 3 A system of three bars with similar cross-section and material supports a vertical…

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Q: Consider the beam shown in (Figure 1). Take P = 2 kip and w = 1.9 kip/ft. Point E is just to the…

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Q: BRONZE BRONZE 30°| 30° 3 m STEEL W = 9.5kN FIGURE B

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Q: For the truss in figure below, the cross-sectional area of the truss members is A=500 mm² and…

A: A truss is given, we need to find out the strain energy.*Note: As per Bartleby's guidelines we are…

Q: 5. A 12-mm-diameter steel [E = 200 GPa] rod (2) is connected to a 30-mm-wide by 8-mm-thick…

A: Given ; Dia of steel rod= 12 mm , E = 200 GPa Dimension of rectangular aluminum bar : Width = 30 mm…

Q: To lower ends of the three bars in the figure two are the same level before the rigid homogeneous…

A: In the question given above, Total weight of the blockW =176 knThus , Ps +Ps+Pb=176 knAs the loading…

Q: 3. The rigid bar AB, attached to two vertical rods as shown in Figure 3, is horizontal before the…

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Q: structural steel rod 1(1)/(2) inches in diameter and 25 feet long, in supporting a balcony, carries…

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Q: The figure below shows a simple form of roof truss, freely supported at X and Y and carrying a…

A: 2KN point load is acting at Z Angle ZYX is 450distance between free supports is 10mFindReactions at…

Q: 5. A 12-mm-diameter steel [E = 200 GPa] rod (2) is connected to a 30-mm-wide by 8-mm-thick…

A: Given data in question  Diameter 12mm Width and thickness 30 × 8 mm Elasticity modulus 200 GPa and…

Q: Problem II. The truss shown in the figure below is applied with force P (refer to the table of…

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Q: Determine the forces in all bars of the truss shown in the given figure. Indicate tension or…

A: The truss shown is symmetrical about its vertical axis passing through C. X = 18 kN Degree of static…

Q: In figure shown the homogenous block weighs 300 kN and the coefficient of friction is 0.40. If h = 5…

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Q: A cantilever beam AB with a circular cross section and length L =750 mm supports a load P =800 N…

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Q: Q 3. A rigid beam AB is 5.5 m long, hinged at point A and supported by two pipes at C and D as shown…

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Q: The force in DB of the truss shown in below figure is W A C O VW tension 5m √3 W compression 2 W…

A: A truss is given we need to find out force in member DB

Q: . Resolve the vector force into its components in the Figure shown. *

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Q: Problem 8.45 The three bars have a weight of WA = 20 lb, WB 40 lb, and Wc = 60 lb, respectively.…

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Q: dị 200 mm a

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Q: • The three steel bars shown in the figure are pin connected to a rigid member. If the applied load…

A: Equilibrium about y:∑ Fy=0FAB+FDC+FEF=15......(a)take moment aboout C:∑ MC=0 -FAB0.4+150.2+FEF0.4=0…