Q9. The 3.9-kg, uniform crate slides up the inclined surface with an initial speed of 11 m/s. If the coefficient of kinetic friction between the crate and the inclined surface is μ = 0.12, determine the distance s the crate has moved when it momentarily stops. (Assume tipping over does not happen, and the slope is long enough.) Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper SI unit. Take g = 9.81 m/s². Your Answer: S Answer 30° units

Q9. The 3.9-kg, uniform crate slides up the inclined surface with an initial speed of 11 m/s. If the coefficient of kinetic friction between the crate and the inclined surface is μ = 0.12, determine the distance s the crate has moved when it momentarily stops. (Assume tipping over does not happen, and the slope is long enough.) Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper SI unit. Take g = 9.81 m/s². Your Answer: S Answer 30° units

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A small boat carrying people with a total weight of 362 Ibs slide down the incline whose dimensions are h=112 ft and d=117 ft. The coefficient of kinetic friction between the boat and the slide is 0.14. Determine the time it takes the boat to go from A to B, use 3 decimals for your answer. The boat starts sliding at A from rest. A d
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Q22. As shown in the image below, the force acting on the 5-kg crate is a function of time. The coefficient of kinetic friction between the crate and the surface is uk = 0.15. Determine the magnitude of the horizontal impulse (in N-s) done by all external forces to the crate during the period from t = 0 to t= 2.3 s. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point. Take g = 9.81 m/s2. %3D F = (201² +30) N (t in second) F = F. 30 V1 Your Answer: Answer
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