The package has a mass of 0.3 kg and slides down the chute from point A at rest. If the kinetic friction coefficient H = B [You may use the Newton's 2nd Law or the energy method). If the curved section BC is frictionless, use the energy method to determine (b) the velocity of the package at point C. Then, detemine (c) the reaction force exerted on the package from the track at point C. Also, determine (d) the horizontal distance d where the package falls on the ground at D. 0.2 on the straight section AB, (a) detemine the velocity of the package when it reaches point 45 02 45 | 6.2 m B 32m D (8] (a) vy = (7) (b) vc [5] (c) FN [5](d) d = 5.6 m
The package has a mass of 0.3 kg and slides down the chute from point A at rest. If the kinetic friction coefficient H = B [You may use the Newton's 2nd Law or the energy method). If the curved section BC is frictionless, use the energy method to determine (b) the velocity of the package at point C. Then, detemine (c) the reaction force exerted on the package from the track at point C. Also, determine (d) the horizontal distance d where the package falls on the ground at D. 0.2 on the straight section AB, (a) detemine the velocity of the package when it reaches point 45 02 45 | 6.2 m B 32m D (8] (a) vy = (7) (b) vc [5] (c) FN [5](d) d = 5.6 m
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Theory and Design for Mechanical Measurements
Measurement is a term that refers to analyzing a manufactured component regarding the degree of accuracy for dimensions, tolerances, geometric profile, roundness, flatness, smoothness, etc. Measurement always involves comparing the manufactured component or the prototype with a standard specimen whose dimensions and other parameters are assumed to be perfect and do not undergo changes with respect to time.Precisely in mechanical engineering the branch that deals with the application of scientific principles for measurements is known as metrology. The domain of metrology in general deals with various measurements like mechanical, chemical, thermodynamic, physical, and biological measurements. In mechanical engineering, the measurements are limited to mechanical specific such as length, mass, surface profile, flatness, roundness, viscosity, heat transfer, etc.
Basic principles of engineering metrology
Metrology is described as the science of measurement, precision, and accuracy. In other words, it is a method of measurement based on units and predefined standards.
Question
Answer all parts to the question please. I have attached a copy of the only formulas we use to solve problems
![Position, Velocity, Acceleration
Rectangular Coordinate:
i = xỉ + yj + zk
ü = v,i + v,j + v,k = xi + ÿj + żk
a = a,i + a,j + a,k = xï + ÿj+ žk
Projectile Motion
a = -gj
v = vĩ + v,j = voxī+(-gt + voy)j
Kinematic Equations for Two Points on the Same
Rigid Body:
%3D
/A
Pure Rolling:
vc = rw; ac = ra, consistent with the rolling direction;
v¡ = 0; a¡ = rw² toward C
7 = xĩ + yỹ = (Voxt + xo)ï + (–gt2 + voyt + Yo)j Eq. of Motion for a Rigid Body in Planar Motion:
1
gt²
ΣF -
Tangent and Normal Coordinate:
* = 7(s)
i = vũ; = sū;
à = a,ū, + a„īn = šū, +ūn
= māg
ΣΜ 1ς α
ΣΜΟ-10α
EMQ = Iga + (Fc/ × mãc),
= lọa + (Tc/Q × māo), Q: any point
G: mass center
O: pivot point or instantaneous center
213/2
1+]
|d²y|
p =
Kinetic Energy of a Rigid Body
dx2
T =mv,² +Igw²
2
Cylindrical Coordinate:
= rū, + zū,
v = v,ũ, + vgũg + v,ū, = rū, + rôūo + żū,
à = a,ūr + agūg + azūz
= (* – rô?)ũ, + (rö + 2řė)ūg + žū,
T =
Work Done on a Rigid Body
- [ Fds + f Mdo
U =
Newton's Second Law:
2F = mã
Work-Energy Principle:
T; +U.-2 = T2
1
kinetic energy: T =
mv²
work done: U =
F• dr
*work of the force exerted by a spring:
U1-2 = k(sỉ – s3)
*work of the force exerted by friction:
U1-2 = -fd
Conservative Force Field:
T1 + Vị = T2 + V2
T: kinetic energy
V:potential energy](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4a02593-47b6-4253-beb0-7c85972c9833%2F339eb509-acc3-4523-9234-df53b3b5a0a8%2F7yv28wo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Position, Velocity, Acceleration
Rectangular Coordinate:
i = xỉ + yj + zk
ü = v,i + v,j + v,k = xi + ÿj + żk
a = a,i + a,j + a,k = xï + ÿj+ žk
Projectile Motion
a = -gj
v = vĩ + v,j = voxī+(-gt + voy)j
Kinematic Equations for Two Points on the Same
Rigid Body:
%3D
/A
Pure Rolling:
vc = rw; ac = ra, consistent with the rolling direction;
v¡ = 0; a¡ = rw² toward C
7 = xĩ + yỹ = (Voxt + xo)ï + (–gt2 + voyt + Yo)j Eq. of Motion for a Rigid Body in Planar Motion:
1
gt²
ΣF -
Tangent and Normal Coordinate:
* = 7(s)
i = vũ; = sū;
à = a,ū, + a„īn = šū, +ūn
= māg
ΣΜ 1ς α
ΣΜΟ-10α
EMQ = Iga + (Fc/ × mãc),
= lọa + (Tc/Q × māo), Q: any point
G: mass center
O: pivot point or instantaneous center
213/2
1+]
|d²y|
p =
Kinetic Energy of a Rigid Body
dx2
T =mv,² +Igw²
2
Cylindrical Coordinate:
= rū, + zū,
v = v,ũ, + vgũg + v,ū, = rū, + rôūo + żū,
à = a,ūr + agūg + azūz
= (* – rô?)ũ, + (rö + 2řė)ūg + žū,
T =
Work Done on a Rigid Body
- [ Fds + f Mdo
U =
Newton's Second Law:
2F = mã
Work-Energy Principle:
T; +U.-2 = T2
1
kinetic energy: T =
mv²
work done: U =
F• dr
*work of the force exerted by a spring:
U1-2 = k(sỉ – s3)
*work of the force exerted by friction:
U1-2 = -fd
Conservative Force Field:
T1 + Vị = T2 + V2
T: kinetic energy
V:potential energy
![The package has a mass of 0.3 kg and slides down the chute from point A at rest. If the kinetic friction
coefficient ug = 0.2 on the straight section AB, (a) determine the velocity of the package when it reaches point
B [You may use the Newton's 2nd Law or the energy method]. If the curved section BC is frictionless, use the
energy method to determine (b) the velocity of the package at point C. Then, determine (c) the reaction force
exerted on the package from the track at point C. Also, detemine (d) the horizontal distance d where the
package falls on the ground at D.
45
02-
45°
6.2 m
в
32 m
[8] (a) v»
(7] (b) vc
[5] (c) Fy =
[5](d) d =
5.6 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4a02593-47b6-4253-beb0-7c85972c9833%2F339eb509-acc3-4523-9234-df53b3b5a0a8%2Fwhprojc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The package has a mass of 0.3 kg and slides down the chute from point A at rest. If the kinetic friction
coefficient ug = 0.2 on the straight section AB, (a) determine the velocity of the package when it reaches point
B [You may use the Newton's 2nd Law or the energy method]. If the curved section BC is frictionless, use the
energy method to determine (b) the velocity of the package at point C. Then, determine (c) the reaction force
exerted on the package from the track at point C. Also, detemine (d) the horizontal distance d where the
package falls on the ground at D.
45
02-
45°
6.2 m
в
32 m
[8] (a) v»
(7] (b) vc
[5] (c) Fy =
[5](d) d =
5.6 m
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