Q8. Nitrogen trifluoride decomposes to form nitrogen and fluorine-gases according to the following equation: 2.6×10 2NF3(g) N2(g) + 3F2(g) X 3X X 3X When (1.54 mol of NF3 is placed in a 6.00-L)container and allowed to come to equilibrium at 800 K, the mixture is found to contain 0.0434 mol of N₂. What is the value of at this temperature? A. 1.54 x 10-5 3.89 X16 Kp = P₂ P²₂ PNE (2-3X16³) (7-3X16³³ (2.6: 10-12 B. 1.91 x 10-3 C. 1.78 × 10-3 D. 1.59 x 10-5 E 5.4 × 10-3 2x_ 2.6x10-2x -8 NF3 = 1,54 = 0.256 = 2.6 - 6.00 T-800 K N2=0.0434 = 0.0072-

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