1) In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) CO2 (g) + H2 (g) In an experiment, 0.25 mol of CO and 0.30 mol of H20 were placed in a 2.00-L reaction vessel. At equilibrium 0.10

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.29QE
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1) In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction:
CO (g) + H2O (g) – CO2 (g) + H2 (g)
In an experiment, 0.25 mol of CO and 0.30 mol of H20 were placed in a 2.00-L reaction vessel. At equilibrium 0.10
mol of CO remains, what is Keq at the temperature?
Transcribed Image Text:1) In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) – CO2 (g) + H2 (g) In an experiment, 0.25 mol of CO and 0.30 mol of H20 were placed in a 2.00-L reaction vessel. At equilibrium 0.10 mol of CO remains, what is Keq at the temperature?
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