(Q56) Consider yttrium iodate, yttrium fluoride, lanthanum iodate, and gallium (III) hydroxide: Yttrium iodate = Y(IO3)3 Ksp = 1.12 x 10-10 Yttrium fluoride = YF3 Ksp = 8.62 x 10-21 %3D Lanthanum iodate = La(IO3)3 Ksp = 7.50 x 10-12 Gallium(III) hydroxide = Ga(OH)3 Kgp = 7.28 x 10-36 %3D Which of the following statements is true regarding the solubilities of these compounds? O They cannot be compared directly because their stoichiometry of dissociation is the same O They cannot be compared directly because their stoichiometry of dissociation is different O They can be compared directly - yttrium iodate is the most soluble O They can be compared directly - gallium(III) hydroxide is the most soluble O They cannot be compared directly because they have different cations and anions

(Q56) Consider yttrium iodate, yttrium fluoride, lanthanum iodate, and gallium (III) hydroxide: Yttrium iodate = Y(IO3)3 Ksp = 1.12 x 10-10 Yttrium fluoride = YF3 Ksp = 8.62 x 10-21 %3D Lanthanum iodate = La(IO3)3 Ksp = 7.50 x 10-12 Gallium(III) hydroxide = Ga(OH)3 Kgp = 7.28 x 10-36 %3D Which of the following statements is true regarding the solubilities of these compounds? O They cannot be compared directly because their stoichiometry of dissociation is the same O They cannot be compared directly because their stoichiometry of dissociation is different O They can be compared directly - yttrium iodate is the most soluble O They can be compared directly - gallium(III) hydroxide is the most soluble O They cannot be compared directly because they have different cations and anions

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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