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Given the following equilibrium constants at 435°C, 1 Na2O(s) = 2 Na(l) + ½ ½ O2(g) K₁ = 6 × 10−25 1 2 NaO(g) = Na(l) + O2(9) Na2O2 (s) 2 Na(1) + O2(g) NaO2(s) Na(1) + O2(g) == K2 = 4 × 10-5 -29 K3 7 x 10 K₁ = 7 × 10-14 determine the values for the equilibrium constants for the following reactions: a. Na2O(8) + O2(g) + Na2O2(s) Equilibrium constant = b. NaO(g) + Na2O(s) = Na2O2 (s) + Na(1) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

Given the following equilibrium constants at 435°C, 1 Na2O(s) = 2 Na(l) + ½ ½ O2(g) K₁ = 6 × 10−25 1 2 NaO(g) = Na(l) + O2(9) Na2O2 (s) 2 Na(1) + O2(g) NaO2(s) Na(1) + O2(g) == K2 = 4 × 10-5 -29 K3 7 x 10 K₁ = 7 × 10-14 determine the values for the equilibrium constants for the following reactions: a. Na2O(8) + O2(g) + Na2O2(s) Equilibrium constant = b. NaO(g) + Na2O(s) = Na2O2 (s) + Na(1) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given the following equilibrium constants at 435°C, 1 Na2O(s) = 2 Na(l) + ½ ½ O2(g) K₁ = 6 × 10−25 1 2 NaO(g) = Na(l) + O2(9) Na2O2 (s) 2 Na(1) + O2(g) NaO2(s) Na(1) + O2(g) == K2 = 4 × 10-5 -29 K3 7 x 10 K₁ = 7 × 10-14 determine the values for the equilibrium constants for the following reactions: a. Na2O(8) + O2(g) + Na2O2(s) Equilibrium constant = b. NaO(g) + Na2O(s) = Na2O2 (s) + Na(1) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)
Transcribed Image Text:Given the following equilibrium constants at 435°C, 1 Na2O(s) = 2 Na(l) + ½ ½ O2(g) K₁ = 6 × 10−25 1 2 NaO(g) = Na(l) + O2(9) Na2O2 (s) 2 Na(1) + O2(g) NaO2(s) Na(1) + O2(g) == K2 = 4 × 10-5 -29 K3 7 x 10 K₁ = 7 × 10-14 determine the values for the equilibrium constants for the following reactions: a. Na2O(8) + O2(g) + Na2O2(s) Equilibrium constant = b. NaO(g) + Na2O(s) = Na2O2 (s) + Na(1) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)
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