The powerful oxidizing agent Ce(IV) can be used to quantitatively determine the concentration of methylmalonic acid (MeMA) in a 500 mL beaker. The reaction proceeds as follows: CH₂CH(COOH) 2 +6Ce(IV) + 2H₂O → CH3COOH + 6Ce(III) + 6H* + 2CO2 If the initial concentration of Ce(IV) in the beaker was 0.3M, and 20.0 mL of 0.5 M Fe2+ was required to back-titrate the excess Ce(IV), what was the concentration of MeMA initially present? A. 0.047 M B. 0.28 M C. 0.020 M D. 0.023 M

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The powerful oxidizing agent Ce(IV) can be used to quantitatively determine the concentration of
methylmalonic acid (MeMA) in a 500 mL beaker.
The reaction proceeds as follows:
CH3CH(COOH)2 + 6Ce(IV) + 2H₂O → CH3COOH + 6Ce(III) + 6H* + 2CO₂
If the initial concentration of Ce(IV) in the beaker was 0.3M, and 20.0 mL of 0.5 M Fe2+ was required
to back-titrate the excess Ce(IV), what was the concentration of Me MA initially present?
A. 0.047 M
B. 0.28 M
C. 0.020 M
D. 0.023 M
Transcribed Image Text:The powerful oxidizing agent Ce(IV) can be used to quantitatively determine the concentration of methylmalonic acid (MeMA) in a 500 mL beaker. The reaction proceeds as follows: CH3CH(COOH)2 + 6Ce(IV) + 2H₂O → CH3COOH + 6Ce(III) + 6H* + 2CO₂ If the initial concentration of Ce(IV) in the beaker was 0.3M, and 20.0 mL of 0.5 M Fe2+ was required to back-titrate the excess Ce(IV), what was the concentration of Me MA initially present? A. 0.047 M B. 0.28 M C. 0.020 M D. 0.023 M
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