Sodium metal reacts with water to produce hydrogen gas according to the following equation: 2Na(s) + 2H20(1)2NAOH(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 744 mm Hg. If the wet H2 gas formed occupies a volume of 9.27 L, the number of moles of Na reacted was mol. The vapor pressure of water is 17.5 mm Hg at 20 °C. Submit Answer Try Another Version 9 item attempts remaining

Chemistry
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Chapter1: Chemical Foundations
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Sodium metal reacts with water to produce hydrogen gas according to the following equation:
2Na(s) + 2H20(1)2NAOH(aq) + H2(g)
The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 744 mm Hg. If the wet H2 gas formed occupies a
volume of 9.27 L, the number of moles of Na reacted was
mol. The vapor pressure of water is 17.5 mm Hg at 20 °C.
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Transcribed Image Text:genow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take ☆ 司(L Update : e [References] Use the References to access important values if needed for this question. Sodium metal reacts with water to produce hydrogen gas according to the following equation: 2Na(s) + 2H20(1)2NAOH(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 744 mm Hg. If the wet H2 gas formed occupies a volume of 9.27 L, the number of moles of Na reacted was mol. The vapor pressure of water is 17.5 mm Hg at 20 °C. Submit Answer Try Another Version 9 item attempts remaining Previous Next
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