Q5. Q6. On walking 300 meters towards a tower in a horizontal line through its base, the measure of the angle of elevation of the top changes from 30° to 60°. Find the height of the tower. The measure of the angle of elevation of the top of a cliff is 25. On walking 100 meters straight towards the cliff, the measure of the angle of elevation of the top is 48°. Find the height of the cliff.

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question
Answer the exercise
100
= 136.60m
0.7321
A pole being broken by the wind, its top struck ground at an angle
of 30° and at a distance of 10m from the foot of the pole. Find the
whole height of the pole.
Let BC= h = height of pole = ?
AD = CD
D
In right A ABD
BD
Tan30⁰
10
BD = 10tan30º = 10(0.5774) = 5.77m
Also
30
10 m
Fig. 6.14
AB
10
10
Cos30⁰ =
⇒AD=.
AD
Cos30⁰
0.8660
Height of pole = h = BD + AD
AD = CD
:.
h = 11.55 +5.77 = 17.32m
h =
Example 7:
Solution:
Q5.
Q6.
A
= 11.55m
Exercise 7.2
e angle of elevation of its top as -
o
on of a kite is 35. The S
of the a
Kite is 340
-meters.
SlovatiON--
of
ht
m from the man IS 32.What
On walking 300 meters towards a tower in a horizontal line
through its base, the measure of the angle of elevation of the top
changes from 30° to 60°. Find the height of the tower.
The measure of the angle of elevation of the top of a cliff is 25. On
walking 100 meters straight towards the cliff, the measure of the
angle of elevation of the top is 48°. Find the height of the cliff.
Transcribed Image Text:100 = 136.60m 0.7321 A pole being broken by the wind, its top struck ground at an angle of 30° and at a distance of 10m from the foot of the pole. Find the whole height of the pole. Let BC= h = height of pole = ? AD = CD D In right A ABD BD Tan30⁰ 10 BD = 10tan30º = 10(0.5774) = 5.77m Also 30 10 m Fig. 6.14 AB 10 10 Cos30⁰ = ⇒AD=. AD Cos30⁰ 0.8660 Height of pole = h = BD + AD AD = CD :. h = 11.55 +5.77 = 17.32m h = Example 7: Solution: Q5. Q6. A = 11.55m Exercise 7.2 e angle of elevation of its top as - o on of a kite is 35. The S of the a Kite is 340 -meters. SlovatiON-- of ht m from the man IS 32.What On walking 300 meters towards a tower in a horizontal line through its base, the measure of the angle of elevation of the top changes from 30° to 60°. Find the height of the tower. The measure of the angle of elevation of the top of a cliff is 25. On walking 100 meters straight towards the cliff, the measure of the angle of elevation of the top is 48°. Find the height of the cliff.
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