Please answer the exercise below 8:58cdn.fbsbx.comDoneV LAI T.1. As the sample size n increases, the sampling distribution of the means approaches a normal distribution.2. The mean of the sampling distribution of means is equal to the mean of the population.fx = μl3. The variance of the sampling distribution of means is equal to the variance of the population divided bythe sample size.0²o² =4. The standard deviation of the sampling distribution of means is equal to the standard deviation of thepopulation divided by the square root of the sample sizeσx==VnExample1:A random sample of n = 49 measurements is obtained from a population with = 192 and = 43.Describe the sampling distribution of means by computing the (a) mean of the sampling distribution ofmeans, and the (b) standard deviation of the sampling distribution of means .SOLUTION: The given are the sample size=49, population mean = 192, and population standarddeviation a = 43.a. Solve for the mean of sampling distribution of means.#₂ = μ since the population mean is 192, therefore the mean of sampling distribution of means is also 192.H₂= 192b. Solve for the standard deviation of the sampling distribution of means.0₂= m430₂=√49430₂ = 7d₂ = 6.1429 or 6.14Example 2:Samples of size n were randomly selected from the population with means and variances given below.In each case, find the mean and the variance of the sampling distribution of the means.a. n36; 44; ²5.76b. n = 45; μ = 40; a² = 5.76Solutions: a. The mean of sampling distribution of means is also 44 since the population mean is 44 (= 44).To find the variance of the sampling distribution of the means, we use oo}73765.7636= 0.16b. The mean of sampling distribution of means is also 40 since the population mean is 40 (μ-40).To find the variance of the sampling distribution of the means, we use a =oof= 15.7645of = 0.128Now it's your turn to practice.Practice ExerciseA. Samples of size n were randomly selected from the population with means and variances givenbelow. In each case, find the mean and the variance of the sampling distribution of the means.1. n = 42; μ = 25; ²= 6.252. n = 30; p = 10; ²9B. A random sample of 264 measurements is obtained from a population with = 60 and 20.Describe the sampling distribution of means by computing the (a) mean of the sampling distribution ofmeans, and the (b) standard deviation of the sampling distribution of means o.Evaluation

Given: A) 1. n=42, μ=25, σ2=6.25

Practice Exercise A. Samples of size n were randomly selected from the population with means and variances given below. In each case, find the mean and the variance of the sampling distribution of the means. 1. n = 42; μ = 25; ²= 6.25 2. n = 30; p = 10; ² = 9 B. A random sample of = 64 measurements is obtained from a population with = 60 and = 20. Describe the sampling distribution of means by computing the (a) mean of the sampling distribution of means #, and the (b) standard deviation of the sampling distribution of means o