### Concrete Pavement Erosion Analysis#### Problem Statement:Given the following information: A concrete pavement for a two-lane highway has doweled joints and no concrete shoulders. The modulus of subgrade reaction is 200 pci (54.2 MN/m³), and the modulus of rupture is 650 psi (4.5 MPa). Assume a load safety factor of 1.1. Truck weight distribution data for a single axle load is as follows:| Axle load (kips) | Multiplied by LSF (1.1) | Expected repetitions | Erosion analysis ||------------------|------------------------|----------------------|---------------------------------|| | | | Allowable repetitions || | | | Erosion percent || | | | || 1 | 2 | 3 | 4 || | | | 5 || | | | || | | | || | | | || | | | |#### Data Table for Single Axles:| Axle Load (kips) | Multiplied by LSF (1.1) | Expected Repetitions | Allowable Repetitions | Erosion (%) | Erosion Factor ||------------------|-------------------------|----------------------|-----------------------|-------------|----------------|| 28 | 30.8 | 5,913 |-----------------------|-------------|----------------|| 26 | 28.6 | 12,483 |-----------------------|-------------|----------------|| 24 | 26.4 | 15,111 |-----------------------|-------------|----------------|| 22 | 24.2 | 102,492 |-----------------------|-------------|----------------|#### Task:Using a trial thickness of 8 inches, fill in the empty spaces using the PCA design method.---### Explanation:The table provides details on various axle loads (in kips), their multiplication by the load safety factor (LSF) of 1.1, and the corresponding expected repetitions for each load. The task involves performing erosion analysis to determine the allowable repetitions and the erosion percentage for each axle load, using a trial pavement thickness of 8 inches. The specific values are to be filled in as per the

Given;Modulus of subgrade reaction = 200 pci = (54.2 MN/m3)Modulus of rupture = 650 pci = (4.5…

Q5. Given the following information: A concrete pavement for two lane highway has doweled joints and no concrete shoulders. The modulus of subgrade reaction is 200 pci (54.2MN/m3), and the modulus of rupture is 650 psi (4.5Mpa). Assume a load safety factor of 1.1. truck weight distribution data for single axle load is as follows: Axle load(kips) Single axles 28 26 Multiplied by LSF (1.1) 24 2 Expected repetitions 30.8 28.6 26.4 3 5,913 12,483 15,111 22 24.2 102,492 Using a trial thickness of 8 in. Fill in the empty spaces using PCA design method Erosion analysis Allowable repetitions 4 6. Erosion factor Erosion percent 5

Q5. Given the following information: A concrete pavement for two lane highway has doweled joints and no concrete shoulders. The modulus of subgrade reaction is 200 pci (54.2MN/m3), and the modulus of rupture is 650 psi (4.5Mpa). Assume a load safety factor of 1.1. truck weight distribution data for single axle load is as follows: Axle load(kips) Single axles 28 26 Multiplied by LSF (1.1) 24 2 Expected repetitions 30.8 28.6 26.4 3 5,913 12,483 15,111 22 24.2 102,492 Using a trial thickness of 8 in. Fill in the empty spaces using PCA design method Erosion analysis Allowable repetitions 4 6. Erosion factor Erosion percent 5

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Capacity and Level of Service at Intersections

The term capacity is associated with transportation engineering. Capacity helps to understand how many pedestrians or vehicles can be handled by a transport facility. Level of service is also a term associated with transportation engineering. The level of service indicates the performance of the transport facility.

Question

### Concrete Pavement Erosion Analysis

#### Problem Statement:
Given the following information: A concrete pavement for a two-lane highway has doweled joints and no concrete shoulders. The modulus of subgrade reaction is 200 pci (54.2 MN/m³), and the modulus of rupture is 650 psi (4.5 MPa). Assume a load safety factor of 1.1. Truck weight distribution data for a single axle load is as follows:

| Axle load (kips) | Multiplied by LSF (1.1) | Expected repetitions | Erosion analysis |
|------------------|------------------------|----------------------|---------------------------------|
| | | | Allowable repetitions |
| | | | Erosion percent |
| | | | |
| 1 | 2 | 3 | 4 |
| | | | 5 |
| | | | |
| | | | |
| | | | |
| | | | |

#### Data Table for Single Axles:

| Axle Load (kips) | Multiplied by LSF (1.1) | Expected Repetitions | Allowable Repetitions | Erosion (%) | Erosion Factor |
|------------------|-------------------------|----------------------|-----------------------|-------------|----------------|
| 28 | 30.8 | 5,913 |-----------------------|-------------|----------------|
| 26 | 28.6 | 12,483 |-----------------------|-------------|----------------|
| 24 | 26.4 | 15,111 |-----------------------|-------------|----------------|
| 22 | 24.2 | 102,492 |-----------------------|-------------|----------------|

#### Task:
Using a trial thickness of 8 inches, fill in the empty spaces using the PCA design method.

---

### Explanation:
The table provides details on various axle loads (in kips), their multiplication by the load safety factor (LSF) of 1.1, and the corresponding expected repetitions for each load. The task involves performing erosion analysis to determine the allowable repetitions and the erosion percentage for each axle load, using a trial pavement thickness of 8 inches. The specific values are to be filled in as per the

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Step 2: Calculating the effective modulus of subgrade reaction.

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Step 3: Calculate the effective wheel load repetitions (N) using the PCA design method.

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Step 4: Determine the allowable repetitions (N'') for each erosion level.

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