Q5: What would happen if you passed in the address of the initialized global variable into releaseEmployee? Would anything different happen if you passed in the address of a local variable (on the stack)?
//below is the code I need help with answering the questions in the image//
#include <stdio.h>
#include <stdlib.h>
struct employees
{
char name[20];
int ssn[9];
int yearBorn, salary;
};
// function to read the employee data from the user
void readEmployee(struct employees *emp)
{
printf("Enter name: ");
gets(emp->name);
printf("Enter ssn: ");
for (int i = 0; i < 9; i++)
scanf("%d", &emp->ssn[i]);
printf("Enter birth year: ");
scanf("%d", &emp->yearBorn);
printf("Enter salary: ");
scanf("%d", &emp->salary);
}
// function to create a pointer of employee type
struct employees *createEmployee()
{
// creating the pointer
struct employees *emp = malloc(sizeof(struct employees));
// function to read the data
readEmployee(emp);
// returning the data
return emp;
}
// function to print the employee data to console
void display(struct employees *e)
{
printf("%s", e->name);
printf(" %d%d%d-%d%d-%d%d%d%d", e->ssn[0], e->ssn[1], e->ssn[2], e->ssn[3], e->ssn[4], e->ssn[5], e->ssn[6], e->ssn[7], e->ssn[8]);
printf(" %d", e->yearBorn);
printf("\n$%d.", e->salary);
}
// function to free the memory of the employee pointer
void releaseEmployee(struct employees *e)
{
free(e);
}
// main method
int main()
{
// creating the employee
struct employees *emp = createEmployee();
// printing the information
display(emp);
// free the memory
releaseEmployee(emp);
return 0;
}
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