Q5 There is a fork() in the road... 9 Points Consider this code using Linux's fork and wait: int x = 1; int main() { if (fork() == 0) { X--; printf(" %d\n", x); exit(0); } else { X++; printf(" %d\n", x); wait (NULL); printf(" %d\n", x); } What are the correct possible outputs (i.e. order of numbers printed) for this code? Enter your answer here To receive credit, please concisely describe your steps below: Enter your answer here

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Q5 There is a fork() in the road...
9 Points
Consider this code using Linux's fork and wait:
int x = 1;
int main() {
if (fork() == 0) {
X--;
printf(" %d\n", x);
exit(0);
else {
X++;
printf(" %d\n", x);
wait (NULL);
X++;
printf(" %d\n", x);
What are the correct possible outputs (i.e. order of numbers printed) for this code?
Enter your answer here
To receive credit, please concisely describe your steps below:
Enter your answer here
Transcribed Image Text:Q5 There is a fork() in the road... 9 Points Consider this code using Linux's fork and wait: int x = 1; int main() { if (fork() == 0) { X--; printf(" %d\n", x); exit(0); else { X++; printf(" %d\n", x); wait (NULL); X++; printf(" %d\n", x); What are the correct possible outputs (i.e. order of numbers printed) for this code? Enter your answer here To receive credit, please concisely describe your steps below: Enter your answer here
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