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Q5/ A ring has a diameter of 21 cm and a cross-section area of 10 cm2. The ring is made up of semicircular sections of cast iron and cast steel, with each joint having a reluctance equal to an air-gap of 0.2 mm. find the ampere-turns required to produce a flux of 8x10-4 Wb. The Neglect fringing and leakage effects. Cast Iron 0.2 mm 21'Cms 0.2 mm Cast Steel

Q5/ A ring has a diameter of 21 cm and a cross-section area of 10 cm2. The ring is made up of semicircular sections of cast iron and cast steel, with each joint having a reluctance equal to an air-gap of 0.2 mm. find the ampere-turns required to produce a flux of 8x10-4 Wb. The Neglect fringing and leakage effects. Cast Iron 0.2 mm 21'Cms 0.2 mm Cast Steel

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Q5/ A ring has a diameter of 21 cm and a cross-section area of 10 cm2. The ring is made up of semicircular sections of cast iron and cast steel, with each joint having a reluctance equal to an air-gap of 0.2 mm. find the ampere-turns required to produce a flux of 8x10-4 Wb. The Neglect fringing and leakage effects. Cast Iron 0.2 mm 21'Cms 0.2 mm Cast Steel
Transcribed Image Text:Q5/ A ring has a diameter of 21 cm and a cross-section area of 10 cm2. The ring is made up of semicircular sections of cast iron and cast steel, with each joint having a reluctance equal to an air-gap of 0.2 mm. find the ampere-turns required to produce a flux of 8x10-4 Wb. The Neglect fringing and leakage effects. Cast Iron 0.2 mm 21'Cms 0.2 mm Cast Steel
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