Q4. The acid base indicator HIn undergoes the following reaction in dilute aqueous solution 10 H+ + In HIn When a 5x10-4 M solution of HIn put in 0.1 M NaOH and in 0.1 M HCl, the following data were obtained. Note that all the indicator will be existing as HIn in 0.1 M HCl and existing as In in NaOH, Solution 0.1 M NaOH 0.1 M HCI A at 485 nm 0.052 0.454 A at 625 nm 0.823 0.176 Calculate a) The molar absorptivity of HIn and In" at 485 and 625 nm b) The acid dissociation constant (Ka) if a small amount of the indicator at pH 5 gave A = 0.472 at 485 nm and A = 0.351 at 625 nm.
Q4. The acid base indicator HIn undergoes the following reaction in dilute aqueous solution 10 H+ + In HIn When a 5x10-4 M solution of HIn put in 0.1 M NaOH and in 0.1 M HCl, the following data were obtained. Note that all the indicator will be existing as HIn in 0.1 M HCl and existing as In in NaOH, Solution 0.1 M NaOH 0.1 M HCI A at 485 nm 0.052 0.454 A at 625 nm 0.823 0.176 Calculate a) The molar absorptivity of HIn and In" at 485 and 625 nm b) The acid dissociation constant (Ka) if a small amount of the indicator at pH 5 gave A = 0.472 at 485 nm and A = 0.351 at 625 nm.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 132IP: A 10.00-g sample of the ionic compound NaA, where A is the anion of a weak acid, was dissolved in...
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Question
![Q4. The acid base indicator HIn undergoes the following reaction in dilute aqueous solution
10 H+ + In
HIn
When a 5x10-4 M solution of HIn put in 0.1 M NaOH and in 0.1 M HCl, the following data
were obtained. Note that all the indicator will be existing as HIn in 0.1 M HCl and existing as
In in NaOH,
Solution
0.1 M NaOH
0.1 M HCI
A at 485 nm
0.052
0.454
A at 625 nm
0.823
0.176
Calculate
a) The molar absorptivity of HIn and In" at 485 and 625 nm
b) The acid dissociation constant (Ka) if a small amount of the indicator at pH 5 gave A
= 0.472 at 485 nm and A = 0.351 at 625 nm.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fda5b54a8-93d2-4914-9166-50d321932b22%2F352287f9-765e-4a5f-b90c-17c449ade5aa%2Fqvowi0e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q4. The acid base indicator HIn undergoes the following reaction in dilute aqueous solution
10 H+ + In
HIn
When a 5x10-4 M solution of HIn put in 0.1 M NaOH and in 0.1 M HCl, the following data
were obtained. Note that all the indicator will be existing as HIn in 0.1 M HCl and existing as
In in NaOH,
Solution
0.1 M NaOH
0.1 M HCI
A at 485 nm
0.052
0.454
A at 625 nm
0.823
0.176
Calculate
a) The molar absorptivity of HIn and In" at 485 and 625 nm
b) The acid dissociation constant (Ka) if a small amount of the indicator at pH 5 gave A
= 0.472 at 485 nm and A = 0.351 at 625 nm.
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