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- Consider the following reaction scheme and complete the unknowns (A) - (E) on the following table iv. As NH, (A) + NH,C (F) (B) Br, H,O 1) EIMgBr 2) H,O NH, pH 4-5 HO OH H-H,0 -H,0 (Е) (D) (A) (B) (D) (C) (E) (F)please show your work too.What is the correct equilibrium constant expression for the following reaction? NH3(aq) + H₂O(1) ⇒NH4*(aq) + OH¯(aq) O O (A) Ke (B) Kc (c) Ke (D) Kc (E) Kc - = = = [NH3] [H₂O] [NH4]+[OH]- [NH4+][OH-] [NH3] [NH4+] [OH [NH3] [H₂O] [NH3] [NH₂+] [OH-] 4 [NH₁+OH [NH3]
- Answer the following by selecting all correct answers. (a) Dynamic equilibrium O is a condition where two opposing processes are occurring at the same rate. O can only occur in water. O is used to describe what happens when weak acids or weak bases are added to water. O is used to describe what happens when strong acids or strong bases are added to water. (b) What will happen if acetic acid (HC2H3O2) is added to water?C(4) Please help me answer this one! I need an urgent answer for this.Can you solve the question in the picture shown?
- G.315.Part D Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur: AX(aq) +BY(aq)→no precipitate AX(aq) + BZ(aq)→precipitate Which of the following choices is insoluble? ► View Avallable Hint(s) O AX O AY O AZ BX O BY BZ Submit Next >Complete the balanced chemical equation for the following reaction between a weak acid and a strong base. H₂S (aq) + KOH(aq) → 2- 3C₂² 1 2 + (s) S 3 K Reset 4 (1) 5 6 LO O 7 (g) ㅈ H 8 9 11 (aq) Submit X 0 • x H₂O
- Complete the balanced neutralization equation for the reaction below: NH,OH(aq) + H,PO,(aq) – O4- 3- | 2+ 3+ O 4+ 1 4 6. 7 8 9. O4 O7 (s) (1) (g) | (aq) + P + Reset • x H,O Delete LO 2. 3.Part B Calculate the concentration of C,H,NH, HạOt, and OH- in a 0.225 M CH,NH Cl solution. (K (C,H,NH2) - 3.9 x 10-10) Express your answer in moles per liter to two significant figures. Enter your answers numerically separated by commas. ? [C,H,NH,). H,O". JOH | = Submit Previous Answers Request AnswerDinitrogen pentoxide forms from its elements by the following balanced chemical equation: 4 NO2 (g) + O2 (g) <--> 2 N2O5 (g) What will be the value of Q if the concentrations are as follows: NO2 = 0.308 M O2 = 0.600 M N2O5 = 0.212 M. ( answer in 3 significant figures)