Q4: IF cache size is 256 byte, if main memory size is 1280 bytes, if last word in block O is 11111. then the number of bits in tag field is . . (using direct mapping) *
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- Q2: a cache memory consists of 512 blocks, and if the last word in the block is 1111111. I the last Tag is 1111. Then the total number of words in main memory is Tags, and The main memory consists of blocks. The total number of bits in address fields i . where number of bits for tag field is .... and the remaining number of bits for word field i ..A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.A cache is set up with a block size of 32 words. There are 16 blocks in cache and set up to be direct map. You have byte address 0x8923. Show the word address, block address, tag, and index. Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0
- For a direct-mapped cache design with 64-bit addresses, the following bits of the address are used to access the cache: Tag Index Offset 63-13 12-4 3-0 a. What is the cache block size (in bytes)?b. What is the cache size (in bytes)?c. What is the total number of bits (including valid bit, tag bits and data array bits) to implement this cache?d. For the same block and cache sizes, you want to implement a 4-way set-associative cache, what is the number of index bit and the number of tag bits?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache.Tag Index Offset31–10 9–5 4–01. What is the cache block size (in words)?2. How many entries does the cache have?3. What is the ratio between total bits required for such a cache implementation over the data storage bits?Starting from power on, the following byte-addressed cache references are recorded. Address 0 4 16 132 232 160 1024 30 140 3100 180 2180 How many blocks are replaced? What is the hit ratio? List the fi nal state of the cache, with each valid entry represented as a record of <index, tag, data>For a direct-mapped cache design with a 32-bit address, the following bitsof the address are used to access the cache. Use the table below. a. What is the cache block size (in words)?b. How many entries does the cache have?c. What is the ration between total bits required for such a cache implementation overthe data storage bit?
- For a direct-mapped cache design with a 32-bit address, the following bits of the address areused to access the cache.Tag Index Offset31–10 9–6 5–0a– What is the cache block size (in words)? b – How many entries does the cache have? c – What is the ratio between total bits required for such a cache implementation overthe data storage bits?What is the operation of a completely associative cache?Which of the cache consistency protocols do you know about?
- If you know that: Tag = 8 bits, Line = 14 bits, and Word= 2 bits for a direct- mapped cache. For the hexadecimal main memory addresses, 888888, what is the value of the "word" field , in hexadecimal format.Describe one of the cache consistency protocolsA 2-way set associative cache consists of four sets. Main memory contains 2K blocks of eight words each. Show the main memory address format that allows us to map addresses from main memory to cache. Be sure to include the fields as well as their sizes. Compute the hit ratio for a program that loops 6 times from locations 8 to 51 in main memory. You may leave the hit ratio in terms of a fraction. Please show details how you obtain the result.