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LCPU assignment Multiply the number by 1.25: A = X * 1.25 X = 0x3C (direct). Then save the result to main memory using direct addressing. Example: Multiply the value by 0.75: X * 0.75 = 0.5 * X + 0.25 * X X = 100 (0x64) 100 * 0.75 = 75 0x64 = 01100100 00110010 [Shift 1x to the right - add 0 to the left and cut off one bit from the right] 00011001 [Shift 2x to the right - add 00 to the left and truncate 2 bits from the right] 01001011 [Sum of previous two transactions] 01001011 = 0x4b = 75

LCPU assignment Multiply the number by 1.25: A = X * 1.25 X = 0x3C (direct). Then save the result to main memory using direct addressing. Example: Multiply the value by 0.75: X * 0.75 = 0.5 * X + 0.25 * X X = 100 (0x64) 100 * 0.75 = 75 0x64 = 01100100 00110010 [Shift 1x to the right - add 0 to the left and cut off one bit from the right] 00011001 [Shift 2x to the right - add 00 to the left and truncate 2 bits from the right] 01001011 [Sum of previous two transactions] 01001011 = 0x4b = 75

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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LCPU assignment

Multiply the number by 1.25: A = X * 1.25
X = 0x3C (direct). Then save the result to main memory using direct addressing.

Example:

Multiply the value by 0.75: X * 0.75 = 0.5 * X + 0.25 * X

X = 100 (0x64)
100 * 0.75 = 75
0x64 = 01100100

00110010 [Shift 1x to the right - add 0 to the left and cut off one bit from the right]
00011001 [Shift 2x to the right - add 00 to the left and truncate 2 bits from the right]
01001011 [Sum of previous two transactions]

01001011 = 0x4b = 75 

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