Q4 (4 pts): Construct a 90% confidence interval of µ̟ - given the following information: mean Sample sd Group 1 20.6 5.3 Group 2 15 19.8 4.5 Hint:[ CI for of H-Pz: X1-X2 ±t@/, as)
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- Two population means are being compared. A sample from population 1 yields data: {105.1, 123.7, 112.5, 107.9, 132.1}. A sample from the population 2 yields data: {125.1, 131.2, 138.9}. Construct a 95% confidence interval for the difference in means, mean of population 2 minus mean of population 1: -Hi• Assume each population is normally distributed. Use the Welch-Saterthwaite t-distribution degrees of freedom. Enter the upper (right) endpoint for the confidence interval.Suppose you have a model Y = B₁ + B₂X₂ + uż that satisfies all CNLRM assumption with 8 observations, and the o2 = 36. What is the 95% confidence interval of o²? (17.17, 98.19) (18.63, 132.46) (17.75, 145.56) (14.95, 174.62) Do not have enough information1:30 PM Wed Apr 21 * 75% 88 Q Apple Pencil •.. 100% Untitled Notebook (1) Stats Exam e) Constret Confalenct Iorval or the predict áge Tor a 75 ycar ola male. Let x*=75 A50 Const ea Prediction Interval for the predd age fo a ale. Let x*-75 2. As concrete cures it gains strength. The following data represents the 7 day and 28 day strength (in pounds per square inch) of a certain type of concrete. 7 Day Strength, x 28 Day Strength, y 2300 4070 3390 5220 2430 4640 2890 4620 3330 4850 2480 4120 3380 5020 2660 4890 2620 4190 3340 4630 a) Calculate r b) Calculate the least regression line c) Test whether there is a linear relationship between 7-day strength and 28-day strength. Let a=0.05 d) Construct a 95% Confidence Interval for the slope of the
- In a sample of n= 19 lichen specimens, the researchers found the mean and standard deviation of the amount of the radioactive element, cesium-137, that was present to be 0.009 and 0.005 microcurie per milliliter, respectively. Suppose the researchers want to increase the sample size in order to estimate the mean u to within 0.002 microcurie per milliliter of its true value, using a 95% confidence interval. Complete parts a through c. a. What is the confidence level desired by the researchers? The confidence level is.Recently, a simple random sample of 572 adult males showed that 124 of them smoke. It has been established that in 2008. 20.4% of adults smoke. Use a 0.05 significance level to test the claim that the rate of smoking by adult males is now the same as in 2008. What is the value of the critical z tabular value?Age x and resting heart rate y were sampled for 25 randomly selected children from age 2 to 9. Summary information is: n = 25, Σx = 140.5, Σx2 = 903.75, Σy = 2567, Σy2 = 264, 457, Σxy = 14, 171.5 (a) Compute a 95% confidence interval for the average resting heart rate of 3 six year old children.
- Preliminary analyses indicate that you can consider the assumptions for using nonpooled t-procedures satisfied. Researchers obtained the following data on the number of acute postoperative days in the hospital using the dynamic and static systems. Obtain a 90% confidence interval for the difference, μ₁ −μ₂, between the mean numbers of acute postoperative days in the hospital with the dynamic and static systems. (Note: x₁ = 7.42, s₁ = 1.38, x₂ = 11.67, and s2 = 4.68) The 90% confidence interval is from to (Round to three decimal places as needed.) 8 7 10 Dynamic 4 8 7 8 60 00 8 8 Static 14 6 8 9 13 7 9 19Statistics QuestionA random sample of size 30 from a normal population yields = 39 and s = 4.9. The lower bound of a 95 percent confidence interval is (Round off upto 2 decimal places).
- dy Pine trees were sampled from each of two blocks of pines, 100 km apart arnd in different rainfall regions. The following summary statistics were obtained: n = 10 I = 12.4 || s = 4.8 n2 = 10 X2 = 16.8 s = = 5.1 i What would be the correct t-value required to calculate a 95% confidence interval for the difference between the means? ii Calculate the 95% confidence interval for the difference between,the two means.Can I get help on what step I missed?Regression methods were used to analyze the data from a study investigating the relationship between roadway surface temperature x₁ = 1478, (x) and pavement deflection (y). Summary quantities were n = 20, Σy; = 12.75, Σy² = 8.86, Σx, Σ x = 143215.8, and Σxy. = 1083.67. Yi Find a 90.0% confidence interval on each of the following: (a) Slope. [i (b) Intercept. [i i i (c) Mean deflection when temperature x = 75 °F. [i i ] (Round your answers to 5 decimal places.) i ] (Round your answers to 3 decimal places.) (d) Find a 90.0% prediction interval on pavement deflection when the temperature is 75 °F. ] (Round your answers to 3 decimal places.) ] (Round your answers to 3 decimal places.)