FORMERY If n=510 and *** fed ************ * ande this *** ** (p-hat) =0.35, find the margin of error at a 95% confidence level Stude
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- Slove the Following: #1. If n=490 and ˆpp^ (p-hat) =0.46, find the margin of error at a 99% confidence level. Give your answer to three decimals #2. In a recent poll, 340 people were asked if they liked dogs, and 31% said they did. Find the margin of error of this poll, at the 95% confidence level. Give your answer to three decimals #3. If n = 540 and ˆpp^ (p-hat) = 0.7, construct a 99% confidence interval.Give your answers to three decimals. #4. Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places. #5. A political candidate has asked you to conduct a poll to determine what percentage of people support her.If the candidate only wants a 4% margin of error at a 95% confidence level, what size of sample is needed? Give your answer in whole people. #6. Assume that a sample is used to estimate a population proportion p. Find the 90%…The researcher recorded the amount of time each bird spent in the plain chamber during a 60-minute session. Suppose the study produced a mean of M = 44.62 minutes on the plain chamber with SS = 206 for a sample of n = 10 birds. Construct the 99% confidence interval to estimate the mean amount of time spent on the plain side for the population of birds. Please type only the lower interval with three decimal places. For example if CI= ( 10.25, 15), then type 10.25 as your answer.An environmentalist wants to find out the fraction of oil tankers that have spills each month. Suppose a sample of 455 tankers is drawn period of these ships, 310 do not have spills. Using the data, construct the 85% confidence interval for the population proportion of oil tankers that have spills each month. Round your answers to 3 decimal places Lower endpoint = Upper endpoint =
- If n=550 and p' (p-prime) = 0.62, construct a 99% confidence interval.Give your answers to three decimals.Alfredo wants a 85% confidence interval for the true average gas mileage for a Gremlin after randomly sampling 9 Gremlins. It is known that the true sigma for Gremlin gas mileage is 4 mpg, and the average of the 9 Gremlins in Alfredo's study was 24 mpg. Find the confidence interval assuming the distribution is normal.what is the " lower limit " and the " upper limit" to this problem ? The mean diastolic blood pressure for a random sample of 150 people was 99 millimeters of mercury. If the standard deviation of individual blood pressure readings is known to be 12 millimeters of mercury, find a 95% confidence interval for the true mean diastolic blood pressure of all people. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place.
- Fron a random sample of 500 Google play apps with more than 1 million installs, 498 are free. Find and interpret a 95% confidence interval for the population proportion of free apps with more than 1 million installs. Write your interval up to 4 decimal places.In an estimation of the confidence interval, increase of the size of the sample will O decrease the margin error. None of these not effect the margin error. increase the margin error.A certain counselor wants to compare mean IQ scores for two different social groups. A random sample of 15 IQ scores from group 1 showed a mean of 117 and a standard deviation of 17 , while an independently chosen random sample of 9 IQ scores from group 2 showed a mean of 112 and a standard deviation of 15 . Assuming that the populations of IQ scores are normally distributed for each of the groups and that the variances of these populations are equal, construct a 90% confidence intervalfor the difference −μ1μ2 between the mean μ1 of IQ scores of group 1 and the mean μ2 of IQ scores of group 2 . Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your responses to at least two decimal places. (If necessary, consult a list of formulas.)
- A research company has carried out a poll to find out about people’s economic outlook. 894 of 1854 young adults (aged between 20–29 years) said that the economic situation is likely to improve over the next year. By contrast, 1292 of 2243 mature adults (aged between 30–39 years) agreed with this statement.) Calculate the upper limit of an 80% confidence interval for the difference between the proportions of people holding this optimistic view in the two age groups in the population. Form the confidence interval around a positive point estimate for the difference between the proportions. In order to obtain a positive point estimate, make sure you subtract the lower value from the higher value when calculating the difference between the sample proportions. Provide your answer as a number between 0 and 1 rounded to 4 decimal places.Solve Question 2 Please show workMr. Roby is trying to estimate the difference in the proportion of his male students who on average sleep fewer than 6 hours per night compared with his female students. He selects a random sample of 20 of his 75 male students and finds that 5 of them sleep fewer than 6 hours per night. He selects another random sample of 17 of his 100 female students and finds that 8 of them sleep fewer than 6 hours a night. Check the conditions for constructing a confidence interval for the difference in proportions. Random condition: A) metB) not metC) does not apply 10% condition: A) metB) not metC) does not apply Large Counts condition: A) metB) not metC) does not apply Are all the conditions for inference met? A) YesB) NoC) Not enough information