q3 can you show every step on how to do the chi square goodness of fit question do that I can understand the steps clearly. Also attached the example formula and chi square critical table  A researcher would like to examine the factors that influence Gen Z purchasing decision  when buying new clothes. The researcher conducted a survey on 160 Gen Z and asked them  to select the most important factor that will influence their purchasing decision. The  frequency distribution is as follows:  Factors Influencing Purchasing Decision  Brand             Style         price       quality    40                       30           30          60  (i) Test at .05 level of significance and indicate whether the data above show any significant  preference among the four factors.  (ii) Compute the effect size .  (iii) Report your findings using APA format, 7th edition.

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q3 can you show every step on how to do the chi square goodness of fit question do that I can understand the steps clearly. Also attached the example formula and chi square critical table

 A researcher would like to examine the factors that influence Gen Z purchasing decision  when buying new clothes. The researcher conducted a survey on 160 Gen Z and asked them  to select the most important factor that will influence their purchasing decision. The  frequency distribution is as follows: 

Factors Influencing Purchasing Decision 

Brand             Style         price       quality

   40                       30           30          60 

(i) Test at .05 level of significance and indicate whether the data above show any significant  preference among the four factors. 

(ii) Compute the effect size . 

(iii) Report your findings using APA format, 7th edition.

BHPY2044 STATISTICAL TECHNIQUES FOR PSYCHOLOGY II
The Chi-Square Distribution*
*The table entries are critical values of x.
Critical
Proportion in Critical Region
0.025
df
0.10
0.05
0.01
0.005
5.02
7.38
6.63
7.88
2.71
4.61
3.84
9.21
10.60
5.99
7.81
2
3
6.25
9.35
I 1.34
12.84
7.78
11.14
13.28
14.86
9.49
11.07
4
5
9.24
12.83
15.09
16,75
14.45
16.81
18.55
10.64
12.02
13.36
12.59
14.07
15.51
7
16.01
18.48
20.28
17.53
20.09
21.96
19.02
21.67
23.59
16.92
18.31
9
14.68
10
15.99
20.48
23.21
25.19
26.76
28.30
29.82
19.68
21.92
24.72
17.28
18.55
19.81
21.06
11
12
21.03
23.34
26.22
24.74
27.69
22.36
23.68
13
14
26.12
29.14
31.32
30.58
32.00
32.80
25.00
26.30
27.49
28.85
15
22.31
16
23.54
34.27
17
24.77
27.59
30.19
33.41
35.72
37.16
38.58
18
25.99
28.87
31.53
34.81
36.19
30.14
31.41
19
27.20
32.85
20
28.41
34.17
37.57
40.00
38.93
40.29
41.40
32.67
33.92
35.17
36.42
37.65
38.89
40,11
41.34
42.56
43.77
35.48
36.78
38.08
39.36
40.65
41.92
43.19
21
29.62
30.81
32.01
42.80
44.18
22
41.64,
42.98
44.31
23
33.20
34.38
35.56
36.74
37.92
39.09
45.56
46.93
48.29
49.64
24
25
26
27
45.64
46.96
48.28
50.99
52.34
53.67
28
44.46
49.59
50.89
29
45.72
30
40.26
46.98
63.69
66.77
59.34
71.42
83.30
95.02
106.63
40
50
51.81
63.17
74.40
85.53
96.58
107.56
118.50
55.76
67.50
76.15
79.49
88.38
100.42
91.95
79.08
90.53
60
70
104.22
112.33
116.32
101.88
113.14
124.34
80
124.12
135.81
118.14
128.30
90
100
129.56
140.17
Table 8 of E. Pearson and H. O. Hartley, Bioinetrika Tables for Statisticians, 3rd ed. New York:
Cambridge University Press, 1966. Adapted and reprinted with permission of the Biometrika
trustees.
Transcribed Image Text:BHPY2044 STATISTICAL TECHNIQUES FOR PSYCHOLOGY II The Chi-Square Distribution* *The table entries are critical values of x. Critical Proportion in Critical Region 0.025 df 0.10 0.05 0.01 0.005 5.02 7.38 6.63 7.88 2.71 4.61 3.84 9.21 10.60 5.99 7.81 2 3 6.25 9.35 I 1.34 12.84 7.78 11.14 13.28 14.86 9.49 11.07 4 5 9.24 12.83 15.09 16,75 14.45 16.81 18.55 10.64 12.02 13.36 12.59 14.07 15.51 7 16.01 18.48 20.28 17.53 20.09 21.96 19.02 21.67 23.59 16.92 18.31 9 14.68 10 15.99 20.48 23.21 25.19 26.76 28.30 29.82 19.68 21.92 24.72 17.28 18.55 19.81 21.06 11 12 21.03 23.34 26.22 24.74 27.69 22.36 23.68 13 14 26.12 29.14 31.32 30.58 32.00 32.80 25.00 26.30 27.49 28.85 15 22.31 16 23.54 34.27 17 24.77 27.59 30.19 33.41 35.72 37.16 38.58 18 25.99 28.87 31.53 34.81 36.19 30.14 31.41 19 27.20 32.85 20 28.41 34.17 37.57 40.00 38.93 40.29 41.40 32.67 33.92 35.17 36.42 37.65 38.89 40,11 41.34 42.56 43.77 35.48 36.78 38.08 39.36 40.65 41.92 43.19 21 29.62 30.81 32.01 42.80 44.18 22 41.64, 42.98 44.31 23 33.20 34.38 35.56 36.74 37.92 39.09 45.56 46.93 48.29 49.64 24 25 26 27 45.64 46.96 48.28 50.99 52.34 53.67 28 44.46 49.59 50.89 29 45.72 30 40.26 46.98 63.69 66.77 59.34 71.42 83.30 95.02 106.63 40 50 51.81 63.17 74.40 85.53 96.58 107.56 118.50 55.76 67.50 76.15 79.49 88.38 100.42 91.95 79.08 90.53 60 70 104.22 112.33 116.32 101.88 113.14 124.34 80 124.12 135.81 118.14 128.30 90 100 129.56 140.17 Table 8 of E. Pearson and H. O. Hartley, Bioinetrika Tables for Statisticians, 3rd ed. New York: Cambridge University Press, 1966. Adapted and reprinted with permission of the Biometrika trustees.
CHI SQUARE GOODNESS OF FIT EXAMPLE QUESTION
1. The following table lists the frequency distribution for 60 rolls of a die.
2-spot
1-spot
Frequency 7
Outcome
3-spot
4-spot
5-spot
6-spot
12
9
14
11
7
Use a =.05 to test whether the die is fair.
STEP 1 Ho: The distribution of the 6 outcomes is the same
H1: The distribution of the 6 outcomes is different
STEP2 LOCATE CRITICAL REGION
df = C – 1
6-1
= 5
Chi square critical value = 11.07 (from chi-square table)
STEP 3 COMPUTE EXPECTED FREQUENCIES
fe = 1/6(60)
= 10
Outcome
1-spot
2-spot
3-spot
4-spot
5-spot
6-spot
fo
7
12
9
14
11
7
fe
10
10
10
10
10
10
STEP 4
x2
(fo - fe)2
Σ
fe
x? = [(7-10):/10] + [(12-10)/10] + [(9-10)/10] + [(14-10)/10] + [(11-10) /10] + [(7-
10)/10]
= 0.9 + 0.4 + 0.1 + 1.6 + 0.1 + 0.9
:4
4 < 11.07, fail to reject Ho
Therefore, the 6 outcomes are equally likely to be obtained. There is no significant
differences in the distribution of outcomes, x'(5, n = 60) = 4, p >.05. The die is fair
Transcribed Image Text:CHI SQUARE GOODNESS OF FIT EXAMPLE QUESTION 1. The following table lists the frequency distribution for 60 rolls of a die. 2-spot 1-spot Frequency 7 Outcome 3-spot 4-spot 5-spot 6-spot 12 9 14 11 7 Use a =.05 to test whether the die is fair. STEP 1 Ho: The distribution of the 6 outcomes is the same H1: The distribution of the 6 outcomes is different STEP2 LOCATE CRITICAL REGION df = C – 1 6-1 = 5 Chi square critical value = 11.07 (from chi-square table) STEP 3 COMPUTE EXPECTED FREQUENCIES fe = 1/6(60) = 10 Outcome 1-spot 2-spot 3-spot 4-spot 5-spot 6-spot fo 7 12 9 14 11 7 fe 10 10 10 10 10 10 STEP 4 x2 (fo - fe)2 Σ fe x? = [(7-10):/10] + [(12-10)/10] + [(9-10)/10] + [(14-10)/10] + [(11-10) /10] + [(7- 10)/10] = 0.9 + 0.4 + 0.1 + 1.6 + 0.1 + 0.9 :4 4 < 11.07, fail to reject Ho Therefore, the 6 outcomes are equally likely to be obtained. There is no significant differences in the distribution of outcomes, x'(5, n = 60) = 4, p >.05. The die is fair
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