Q3: A 600 kVA, single phase transformer has iron loss 500 W and copper loss 950 W if the power factor of the load is 0.75 lagging. Calculate a- Half full load efficiency. b- The maximum efficiency. c- The all-day efficiency when the transformer operated through 24 hours: Time period 2a. m-10a.m 10 a.m-8p.m 8 р.m. — 10 р.m. 10 p.m -2am Load Power factor No load 0.8 lagging Unity 450 kVA 600 kVA No load

Q3: A 600 kVA, single phase transformer has iron loss 500 W and copper loss 950 W if the power factor of the load is 0.75 lagging. Calculate a- Half full load efficiency. b- The maximum efficiency. c- The all-day efficiency when the transformer operated through 24 hours: Time period 2a. m-10a.m 10 a.m-8p.m 8 р.m. — 10 р.m. 10 p.m -2am Load Power factor No load 0.8 lagging Unity 450 kVA 600 kVA No load

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

1. What would be the standard burden designation for a potential transformer operating at a 0.85 pf and with a burden of 75 VA? A. W B. M C. Y D. X
Question 2. Consider a 10 KVA, 200/400 V, 50 Hz single-phase transformer has the following test results: O.C. test: 200 V, 0.6 A, 63 W (L.V. side) S.C. test : 20 V, 25 A, 85 W (H.V. side) Determine : i) The efficiency at 75 % of full-load at 0.9 leading power factor. ii) The secondary terminal voltage on fiull-load at unity power factor.
(B)- Draw the graph of efficiency against load current when the transformer is loaded
2- Determine the number of turns per-phase in each winding of a 3-phase transformer with a ratio of 20000/2000v. to work on a 50Hz network. The high-voltage winding is delta connected and the low-voltage is star-connected. Each core has a gross sectional area of 560 cm². Assume a flux density of about 1.2 wb/m². [1490/86]
B- the eddy current losses of 400V, 50 Hz transformer is 1600W and the total iron losses i 2500W. calculate the iron losses at 200V, 25 Hz.
The test results of a 5 kVA, 400/200 V, 50 Hz, single phase transformer are as follows. O.C. Test: 400 V, 1 A, 50 W, H.V. side S.C. Test: 12 V, 12.5 A, 60 W, H.V. side Find the full load efficiency and regulation when the power factor is 0.8 lagging.
A 120 kVA, 1350/330 V single phase transformer has the following parameters: R1 = 0.34 Q, X1 = 0.59 0, R2 = 0.014 Q, X1 = 0.029 Q, Rc = 380 and Xm = 320 Q. The no load current is 4.7 A at a power factor of 0.36 lagging and the no load losses are 4.6 kW. For a full load and 0.9 power factor lagging with 300 V load terminal voltage, determine (a) equivalent circuit parameters referred to primary side, (b) percentage regulation and (c) full load efficiency. O:01 AM
Current transformer has Select one: O a. No relation between primary windings and its secondary windings O b. More secondary windings than its primary windings O C. Primary windings equal to secondary windings O d. More primary windings than its secondary windings
c) A 100 kVA, 4500/250 V, 50 Hz single-phase transformer has 100 secondary turns.Determine: i.The primary current.ii.The secondary current.iii.The number of primary turns.
transformrs
4. Why the efficiency of the transformer is high at half load compared to full load?
Following are the results of a test carried out on a 230/600 V single phase, 7.5 kVA transformer. O.C. Test : 230 V, 1.2 A, 280 W, on L.V side S.C. Test : LV winding is shorted. 26 V, 11A, 155 W, H.V. Both the full load efficiency and full load regulation of the transformer on the side are 0.8 lagging p.f Search on.