Q3 A 120 HP DC shunt motor is connected to a voltage supply of 240 V. The armature draws a nominal current of 400 A. The motor is currently running at 800 rpm and it is required to stop this motor using dynamic breaking method. a) Calculate the breaking resistance required such that at the instant of breaking the armature current does not exceed 125 % of nominal armature current. b) Calculate the time constant, To, if the moment of inertia is 300 Kg.m² with the breaking resistance you found in part (a) above.

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Q3 A 120 HP DC shunt motor is connected to a voltage supply of 240 V. The armature draws a
nominal current of 400 A. The motor is currently running at 800 rpm and it is required to stop
this motor using dynamic breaking method.
a) Calculate the breaking resistance required such that at the instant of breaking the
armature current does not exceed 125 % of nominal armature current.
b) Calculate the time constant, To, if the moment of inertia is 300 Kg.m with the breaking
resistance you found in part (a) above.
c) Determine the time required time for the motor speed to reach 25 rpm, using the time
constant you found in part (b) above.
ANS. [R=0.48 Q, To = 12 sec., 60 sec.]
Transcribed Image Text:Q3 A 120 HP DC shunt motor is connected to a voltage supply of 240 V. The armature draws a nominal current of 400 A. The motor is currently running at 800 rpm and it is required to stop this motor using dynamic breaking method. a) Calculate the breaking resistance required such that at the instant of breaking the armature current does not exceed 125 % of nominal armature current. b) Calculate the time constant, To, if the moment of inertia is 300 Kg.m with the breaking resistance you found in part (a) above. c) Determine the time required time for the motor speed to reach 25 rpm, using the time constant you found in part (b) above. ANS. [R=0.48 Q, To = 12 sec., 60 sec.]
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