Q2- For the network shown below, compute the corrected flow rates in all pipes after one correction step (after one AQ). 150L/s B Given data: Pipe ID Length(m) Diameter(mm) AB 200 250 100L/s AC 150 200 A 50L/s BC 250 250 fAR = fac = fBc_=f= 0.016 QAB = 50 L/s

Q2- For the network shown below, compute the corrected flow rates in all pipes after one correction step (after one AQ). 150L/s B Given data: Pipe ID Length(m) Diameter(mm) AB 200 250 100L/s AC 150 200 A 50L/s BC 250 250 fAR = fac = fBc_=f= 0.016 QAB = 50 L/s

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Fluid Materials

In general terms, anything that flows can be termed as a fluid. In other words, a fluid is any substance that cannot resist shear forces and deforms continuously under the application of external shear forces. Fluid materials differ completely from solid materials such as metals and alloys. For instance, if we consider two infinitesimally small cross-sectional areas of fluid materials and solid materials, and apply shear forces to these elements, both the elements will undergo deformation. Upon releasing the shear force, the element of the solid materials will regain its original orientation, but the element of the fluid materials will keep on deforming continuously under the action of the shear force.

Question

Q2- For the network shown below, compute the corrected flow rates in all pipes after one
correction step (after one AQ).
150L/s
B
Given data:
Pipe ID
Length(m)
Diameter(mm)
AB
200
250
100L/s
AC
150
200
A
50L/s
BC
250
250
fAR = fac = fBc_=f= 0.016
QAB = 50 L/s

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