In the context of a sewer system, you need to find the optimal diameter (DD) of a pipe to meet a design flow rate (QdQd) and a maximum allowed flow depth percentage (y/Dy/D). Utilize the flow velocity equation: V = -2 * SQRT(8 * g * R * S) * LOG10((ks / (14.8 * R)) + (2.51 * μ / (4 * ρ * R * SQRT(8 * g * R * S))) Given:
In the context of a sewer system, you need to find the optimal diameter (DD) of a pipe to meet a design flow rate (QdQd) and a maximum allowed flow depth percentage (y/Dy/D). Utilize the flow velocity equation: V = -2 * SQRT(8 * g * R * S) * LOG10((ks / (14.8 * R)) + (2.51 * μ / (4 * ρ * R * SQRT(8 * g * R * S))) Given:
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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In the context of a sewer system, you need to find the optimal diameter (DD) of a pipe to meet a design flow rate (QdQd) and a maximum allowed flow depth percentage (y/Dy/D). Utilize the flow velocity equation: V = -2 * SQRT(8 * g * R * S) * LOG10((ks / (14.8 * R)) + (2.51 * μ / (4 * ρ * R * SQRT(8 * g * R * S)))
Given:
- Design flow rate (Qd): 4.12 m³/s
- Pipe slope (S): 0.01
- Pipe roughness (ks): 1.50E-06 m
- Maximum flow depth percentage (y/D): 85%
- Fluid density (ρ): 999.1 kg/m³
- Fluid viscosity (μ): 1.14E-03 Pa*s
- Acceleration due to gravity (g): 9.81 m/s²
- Pipe diameter (D): 1.000 m
Transcribed Image Text:V = -2√/8gRS log10 (14 2.51μ
+
ks
14.8R
4pR√8gRS
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