Q1:A shaft carry ing two pulleys I and 2, and supported on two bearings A and B. The shaft transmits a power of 7.5 kW at 360 rpm trom the pulley 1 to the nulley 2 liameters of pulleys 1 and 2 are 250 mim and 500 mm respectively. The masses of pulleys 1 and2 are 1 ad 30 kg respectively. The belt tensions act vertically downward and the ratio of belt tensions on the tight eid lack side for each pulley is 2.5:1. The shaft is made of plain carbon steel, the Permissible shear stress is 63.333 MPa and the factor of safety is . 1- Find the total force acting at the centre line of the pulley 1 and 2 and 2- Estimate suitable diameter of shaft, Assume G = 79300 MPa. 250 500 250 Px 60 T = 2n N = l.0 2.3 log T, T = (T-T,) Re 1, - JM² + T =**xd (а) %3D T4 T, 0----

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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kW at 360 rpm from the pulley 1 to the pulley 2. The diameters of pulleys 1 and 2 are 250 mm and 500 mm
Q1:A shaft carry ing two pulleys I and 2, and supported on two bearings A and B. The shaft transmits a power of 7.5
respectively. The masses of pulleys 1 and 2 are 10 ko qnd 30 kg respectively. The belt tensions act vertically
downward and the ratio of belt tensions on the tight si alack side for each pulley is 2.5:1. The shaft is made of
plain carbon steel, the Permissible shear stress is 63.333 MMPg and the factor of safety is .
1- Find the total force acting at the centre line of the pulley I and 2 and
2-
Estimate suitable diameter of shaft, Assume G = 79300 MPa.
250
500
250
Px 60
T =
2n N
2.3 log
= L1.0
3 (T-T,) Rc
(а)
T = JM? +T
IxTx d
=-X
16
T T1
Tz T3
|र---.
Transcribed Image Text:kW at 360 rpm from the pulley 1 to the pulley 2. The diameters of pulleys 1 and 2 are 250 mm and 500 mm Q1:A shaft carry ing two pulleys I and 2, and supported on two bearings A and B. The shaft transmits a power of 7.5 respectively. The masses of pulleys 1 and 2 are 10 ko qnd 30 kg respectively. The belt tensions act vertically downward and the ratio of belt tensions on the tight si alack side for each pulley is 2.5:1. The shaft is made of plain carbon steel, the Permissible shear stress is 63.333 MMPg and the factor of safety is . 1- Find the total force acting at the centre line of the pulley I and 2 and 2- Estimate suitable diameter of shaft, Assume G = 79300 MPa. 250 500 250 Px 60 T = 2n N 2.3 log = L1.0 3 (T-T,) Rc (а) T = JM? +T IxTx d =-X 16 T T1 Tz T3 |र---.
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